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damaskus [11]
3 years ago
8

Can a 3 foot-by-9 foot rectangle be a scaled copy of a 3 foot-by-1 foot rectangle? Explain

Mathematics
1 answer:
Bumek [7]3 years ago
7 0
No,because 9 feet is way bigger than 1 foot.
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A $1,500 savings bond earns simple interest at the rate of 5% each year. The interest is paid at the end of every month. How muc
kirill [66]

Answer:

300

Step-by-step explanation:

5 percent * 6000

(5:100)* 6000

(5* 6000):100

30000:100 = 300

4 0
3 years ago
Read 2 more answers
No irrational numbers are whole numbers. True or false and why?
Luda [366]
Hi!

Irrational numbers cannot be whole numbers. In order to be a whole number, you cannot have any decimals or fractions. Irrational numbers possess these properties.

Hopefully, this helps! =)
4 0
3 years ago
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On Thursday, a local hamburger shop sold a combined total of 444 hamburgers and cheeseburgers. The number of cheeseburgers sold
krek1111 [17]

Answer:

They sold 111 Hamburgers

Step-by-step explanation:

Turn this into an equation: first, take the amount of hamburgers and call it 3x due to it being 3 times more than the amount of cheeseburgers, which we will can call x.

So, X+3X=444 is what you need to solve this. This is the same as 4x=444

So, x=111

Now, Input 111 for the final answer; 333 cheeseburgers and 111 hamburgers

5 0
3 years ago
I need help please???
alexdok [17]

Answer:

x<29

Step-by-step explanation:

This would be the BEST answer. Hope it helps! ☺

4 0
3 years ago
Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,
creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by a_0=0 a_n=a_{n-1}+3n-1

To find : Write out the first 5 terms of this sequence ?

Solution :

a_n=a_{n-1}+3n-1 and a_0=0

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

a_1=a_{1-1}+3(1)-1

a_1=a_{0}+3-1

a_1=0+2

a_1=2

For n=2,

a_2=a_{2-1}+3(2)-1

a_2=a_{1}+6-1

a_2=2+5

a_2=7

For n=3,

a_3=a_{3-1}+3(3)-1

a_3=a_{2}+9-1

a_3=7+8

a_3=15

For n=4,

a_4=a_{4-1}+3(4)-1

a_4=a_{3}+12-1

a_4=15+11

a_4=26

For n=5,

a_5=a_{5-1}+3(5)-1

a_5=a_{4}+15-1

a_5=26+14

a_5=40

The first 5 terms of the sequence is 2,7,15,26,40.

5 0
3 years ago
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