Kepler's third law described the relation between semi-major axis (or average distance to the star) and
the orbital period (how long it takes to complete one lap) as follows:
a^3 / p^2 = constant
In the case of our Solar system the constant is 1
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU
Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
Answer:
3, 6, 9, 12 is not geometric
Step-by-step explanation:
A geometric progression has a common ratio r between consecutive terms.
3, 6, 9 , 12
has a common difference of 3 between terms and is arithmetic
1, 5, 25, 125
r = 5 ÷ 1 = 25 ÷ 5 = 125 ÷ 25 = 5 ← geometric
4, 8, 16, 32
r = 8 ÷ 4 = 16 ÷ 8 = 32 ÷ 16 = 2 ← geometric
2, 6, 18, 54
r = 6 ÷ 2 = 18 ÷ 6 = 54 ÷ 18 = 3 ← geometric
Answer:
The minor arc PR is 42 degrees
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The inscribed angle is half that of the arc comprising
so
we have
substitute
Remember that the minor arc in a circle is less than 180 degrees
therefore
The minor arc PR is 42 degrees
Step-by-step explanation:
Equation; j/9 = 5
j = 9 × 5
j = 45
Answer:
D is the solution
Step-by-step explanation:
1.25 = 1.25/100= 125%
1 1/4= 1 25/100 = 1.25
125%= 125/100= 1.25 and 1 1/4
