Answer:
The probability of 1 or less children from that group to learn how to swim before 6 years of age is 0.072
Step-by-step explanation:
In this case we need to compute the probability of none of these 12 children learns to swim before 6 years of age. This is given by:
p(0) = (1 - 0.312)^(12) = 0.688^(12) = 0.01124
We now need to calculate the probability that one child learns to swim before 6 years of age.
p(1) = 12*0.312*(1 - 0.312)^(11) = 3.744*(0.688)^(11)
p(1) = 3.744*0.01634
p(1) = 0.0612
The probability of 1 or less children from that group to learn how to swim before 6 years of age is:
p = p(0) + p(1) = 0.01124 + 0.0612 = 0.07244
Step-by-step explanation:
y - 3 = -1(x- -2)
y-3 = -x -2
Y = -x +1
Simple.....
always remember the y-intercept is where your line hits the y-axis... or where it hits the vertical axis...
As we can see this line hits the y-axis at (0,3)-->> y-intercept=3
Thus, your answer.
It is 5:9 in simplest form
7/10 > 3/8
I found this by first finding a common denominator, so for this it will be 40. 10 can go into 40 four times, so you do 7x4 and that is 28, so 7/10 is 28/40.
3/8 is 15/40 because 8 goes into 40 five times, so you do 5x3 which is 15, so the fraction is 15/40. 15/40 is less than 28/40 because 28 > 15
