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blagie [28]
3 years ago
7

Giles is searching for a sock and discovers that he has 10 socks for every 5 pairs of shoes. If he has 20 socks, how many pairs

of shoes does he have? Show your work. Explain.
Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0
The answer is 10 pairs of shoes.
The first ratio is 10:5. 10 socks per 5 pairs of shoes. You have 20 socks now instead of 10. You just double the ratio. 20 socks per 10 pairs of shoes. 20:10.
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3 years ago
Slope point form<br> passing through (4,-7) with x intercept = -4
r-ruslan [8.4K]

Answer:

We start with this equation:

If x intercept is -4 then y = 0 giving us another point (-4, 0)

(4, -7) and (-4, 0)

slope = y difference / x difference = (-7 -0) / (4 --4) =

-7 / 8

Step-by-step explanation:

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4 years ago
You play in a soccer tournament, that consists of 5 games. Each game you win with probability .6, lose with probability .3, and
nasty-shy [4]

Answer:

(a) The joint PMF of W, L and T is:

P(W,\ L,\ T)={5\choose (n_{W}!\times n_{L}!\times n_{T}!)}\times [0.60]^{n_{W}}\times [0.30]^{n_{L}}\times [0.10]^{n_{T}}

(b) The marginal PMF of W is:

P(W=w)={5\choose n_{W}!}\times 0.60^{n_{W}}\times (1-0.60)^{n-n_{W}}

Step-by-step explanation:

Let <em>X</em> = number of soccer games played.

The outcome of the random variable <em>X</em> are:

<em>W</em> = if a game won

<em>L</em> = if a game is lost

<em>T</em> = if there is a tie

The probability of winning a game is, P (<em>W</em>) = 0.60.

The probability of losing a game is, P (<em>L</em>) = 0.30.

The probability of a tie is, P (<em>T</em>) = 0.10.

The sum of the probabilities of the outcomes of <em>X</em> are:

P (W) + P (L) + P (T) = 0.60 + 0.30 + 0.10 = 1.00

Thus, the distribution of W, L and T is a appropriate probability distribution.

(a)

Now, the outcomes W, L and T are one experiment.

The distribution of <em>n</em> independent and repeated trials, each having a discrete number of outcomes, each outcome occurring with a distinct  constant probability is known as a Multinomial distribution.

The outcomes of <em>X</em> follows a Multinomial distribution.

The joint probability mass function of <em>W</em>, <em>L</em> and <em>T</em> is:

P(W,\ L,\ T)={n\choose (n_{W}!\times n_{L}!\times n_{T}!)}\times [P(W)]^{n_{W}}\times [P(L)]^{n_{L}}\times [P(T)]^{n_{T}}

The  soccer tournament consists of <em>n</em> = 5 games.

Then the joint PMF of W, L and T is:

P(W,\ L,\ T)={5\choose (n_{W}!\times n_{L}!\times n_{T}!)}\times [0.60]^{n_{W}}\times [0.30]^{n_{L}}\times [0.10]^{n_{T}}

(b)

The random variable <em>W</em> is defined as the number games won in the soccer tournament.

The probability of winning a game is, P (W) = <em>p</em> = 0.60.

Total number of games in the tournament is, <em>n</em> = 5.

A game is won independently of the others.

The random variable <em>W</em> follows a Binomial distribution.

The probability mass function of <em>W</em> is:

P(W=w)={5\choose n_{W}!}\times 0.60^{n_{W}}\times (1-0.60)^{n-n_{W}}

Thus, the marginal PMF of W is:

P(W=w)={5\choose n_{W}!}\times 0.60^{n_{W}}\times (1-0.60)^{n-n_{W}}

3 0
3 years ago
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dimaraw [331]

Answer:

1

Step-by-step explanation:

<em>13  15  </em>17  <u>x</u>  <em>20  21</em>

<em>Cross out all outer numbers</em>

We are left with 17 and x

With double medians, you add those two together and then divide them by two.

With the median (total) being 18, we will first add 17+x then divide Y/2 = 18

The value of x is 1

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A rectangle has a perimeter of 78 inches. Its length is 6 inches more than<br> twice its width.
Ratling [72]

Answer:

Step-by-step explanation:

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3 years ago
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