What's the square root of 2 rounded to the nearest tenth ?
2 answers:
You might be interested in
Answer:
The answer is
<h2>12.3 cm</h2>Step-by-step explanation:
Since the triangle is a right angled triangle we can use trigonometric ratios to find y
To find y we use cosine
cos∅ = adjacent / hypotenuse
From the question
y is the adjacent
The hypotenuse is 15
So we have
We have the final answer as
<h3>12.3 cm to the nearest tenth</h3>Hope this helps you
Answer
B)
Step by step explanation
The standard form of circle when center(h, k) and radius r, given is
(x - h)^2 + (y - k)^2 = r^2
Given: (h, k) = (5, 0) and r = 3
Now plug in these values in the standard form, we get
(x - 5)^2 + (y - 0)^2 = 3^2
Therefore, the answer is B)
Thank you :)