Answer:
See explanation
Explanation:
The chlorination of benzene occurs in the presence of a Lewis acid. A Lewis acid is a compound that can accept a lone pair of electrons.
The first step in the chlorination of benzene is the formation of the ion Cl^+ which attacks the benzene ring.
This ion is formed when the Cl2 molecule undergoes heterolytic fission assisted by FeCl3 to yield FeCl4^- and Cl^+.
The Cl^+ electrophile now attacks the benzene ring to yield chlorobenzene.
Answer : Option C) The polar bonds are oriented in opposite direction.
Explanation : A molecule of carbon dioxide contains two polar covalent bonds. This molecule is non-polar because the polar bonds are oriented in the opposite direction.
In order to be a polar molecule, carbon dioxide must have both a slightly negative side and a slightly positive side in its molecule. The orientation of the lone pairs of electrons present on each oxygen atom cancels each other, making the molecule non polar.
Answer: its a
Explanation:
just took my quiz on edge 2020
<u>Answer:</u> The standard enthalpy of formation of is -92.7 kJ/mol
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate enthalpy change is of a reaction is:
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the standard enthalpy of formation of is -92.7 kJ/mol
V ( HCl ) = 16.4 mL / 1000 => 0.0164 L
M( HCl) = ?
V( KOH) = 12.7 mL / 1000 => 0.0127 L
M(KOH) = 0.620 M
Number of moles KOH:
n = M x V
n = 0.620 x 0.0127
n = 0.007874 moles of KOH
number of moles HCl :
<span>HCl + KOH = H2O + KCl
</span>
1 mole HCl ------ 1 mole KOH
<span>? mole HCl--------0.007874 moles KOH
</span>
moles HCl = 0.007874 * 1 / 1
= 0.007874 moles of HCl
M = n / V
M = 0.007874 / <span>0.0164
</span>= 0.480 M
Answer (2)
hope this helps!