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Evgen [1.6K]
2 years ago
7

An iron pipe has a density of 7.86 g/mL and a volume of 324.4 mL. What is the mass of the iron pipe?

Chemistry
1 answer:
wlad13 [49]2 years ago
6 0

Answer:

Mass=2549.784 \ g

Explanation:

The equation for mass is:

Mass = Density * Volume

We plug in the given values into the equation:

Mass = 7.86 \ g/mL * 324.4 \ mL

Mass=2549.784 \ g

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30 g of hydrogen reacts with 120 g of oxygen to form water.How much water is produced?
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According to law of conservation of mass.

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Explain,using your own example ,why you must always give a unit when reporting a measurement
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Consider 4.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.80 L and the temperature is increased to 3
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This is an exercise in<u> the General Combined Gas Law</u>.

To start solving this exercise, we obtain the following data:

<h3>Data:</h3>
  • V₁ = 4.00 l
  • P₁ = 365 mmHg
  • T₁ = 20 °C + 273 = 293 K
  • V₂ = 2,80 l
  • T₂ = 30 °C + 273 = 303 K
  • P₂ = ¿?

We apply the following formula:

  • P₁V₁T₂=P₂V₂T₁     ⇒  General formula

Where:

  • P₁=Initial pressure
  • V₁=Initial volume
  • T₂=end temperature
  • P₂=end pressure
  • T₂=end temperature
  • V₁=Initial temperature

We clear for final pressure (P2)

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}

We substitute our data into the formula:

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})}  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 }  \end{gathered}$}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}

Answer: The new canister pressure is 539.224 mmHg.

<h2>{ Pisces04 }</h2>
6 0
2 years ago
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