Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
No a repeating decimals have number repeating such as 555555.
let y = x^2
4y^2 -21y + 20 = 0
solve for y
then substitute back in to get x
Step-by-step explanation:
<em>Given </em>
<em>circumference </em><em>=</em><em> </em><em>1</em><em>2</em><em> </em><em>inch</em>
<em>π</em><em> </em><em>=</em><em> </em><em>3</em><em>.</em><em>1</em><em>4</em>
<em>radius </em><em>(</em><em>r) </em><em> </em><em>=</em><em> </em><em>?</em>
<em>We </em><em>know </em>
<em>circumference </em><em>=</em><em> </em><em>2</em><em>π</em><em>r </em>
<em>1</em><em>2</em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>*</em><em> </em><em>3</em><em>.</em><em>1</em><em>4</em><em> </em><em>*</em><em> </em><em>r</em>
<em>r </em><em>=</em><em> </em><em>1</em><em>2</em><em> </em><em>/</em><em> </em><em>6</em><em>.</em><em>2</em><em>8</em>
<em>Therefore </em><em> </em><em>r </em><em>=</em><em> </em><em>1</em><em>.</em><em>9</em><em>1</em><em> </em><em>inch</em>
Well using distance formula we get the length of ab to be 3, knowing a'b'=6 we know the dilator must be 2