What are the zeroes of P(x) = x3 – 6x2 - x +62

Mathematics

1 answer:

Maurinko [17]3 years ago

4 0

Answer:

x = 6

x = -1

x = 1

Step-by-step explanation:

Given:

Correct equation;

P(x) = x³ - 6x² - x + 6

Computation:

x³ - 6x² - x + 6

x²(x-6)-1(x-6)

(x-6)(x²-1)

we know that;

a²-b² = (a+b)(a-b)

So,

(x-6)(x²-1)

(x-6)(x+1)(x-1)

So,

zeroes are;

x = 6

x = -1

x = 1

You might be interested in

The top tree broke and fell over.the remaining tree teunk is 3 feet tall.the tip of the tree rests on the ground 14 feet from th

Bas_tet [7]

Answer:

14.3 feet.

14.3 feet

Step-by-step explanation:

The problem forms a right triangle in which:

The Vertical Leg of the Right Triangle = 3 feet

The Horizontal Leg of the Right Triangle =14 feet

We are to determine the length of the broken part of the tree. This is the Hypotenuse of the Right Triangle,

Using Pythagoras Theorem

$Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=14^2+3^2\\Hypotenuse^2=205\\Hypotenuse=\sqrt{205}\\Hypotenuse=14.32\\ \approx 14.3 feet $(to the nearest tenth of a foot).\\Therefore, the lenght of the broken part of the tree to the nearest tenth of a foot is 14.3 feet.$