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Mandarinka [93]
3 years ago
14

Who are the most powerful leaders in Congress?

Advanced Placement (AP)
1 answer:
Bingel [31]3 years ago
5 0

Answer:

With the Democrats holding a majority of seats and the Republicans holding a minority, the current leaders are: Majority Leader Steny Hoyer, Majority Whip Jim Clyburn, Minority Leader Kevin McCarthy and Minority Whip Steve Scalise enjoy :)

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According to the statement of Madison who holds supreme power under the consitution?
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According to the statement of Madison The People hold the supreme power under the constitution because as Madison says The powers granted by the  proposed Constitution are the gift of  the people, and may be resumed by  them when reverted to their oppression and every power not granted  thereby remains with the people.

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  It's important to recognize children when they follow the rules because not doing so can​
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not recognizing children when they do good and follow rules makes them fell as if they are unrecognised and may lead to them not following rules and doing right

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Pag tama ng panganib​
Zinaida [17]
Wait is this Spanish ? Or you just giving free points ?
4 0
3 years ago
My fellow math brodas, help
DiKsa [7]

A. Depending on which variable you choose to integrate with, you can capture the total bounded region with either -2 ≤ x ≤ (-1 + √5)/2 or 1 ≤ y ≤ (5 + √5)/2, where the upper endpoints correspond to the coordinates of the appropriate intersections:

y = x² + 1

⇒   x = (x² - 2)² - 2

⇒   x⁴ - 4x² - x + 2 = 0

⇒   (x - 2) (x + 1) (x² + x - 1) = 0

⇒   x = 2, x = -1, x = -1/2 ± √5/2

⇒   y = 5, y = 2, y = (5 ± √5)/2

On the other hand, we can compute the areas of A and B separately, then sum those integrals. Area A is easier to compute by integrating with respect to y over 2 ≤ y ≤ (5 + √5)/2, while area B is easier to find by integrating x over -1 ≤ x ≤ (-1 + √5)/2.

B. I'll stick to the split-region approach.

First, we find equations for the appropriates halves of either parabola:

• y = x² + 1   ⇒   x = ± √(y - 1)

and x = -√(y - 1) describes the left half of the blue parabola;

• x = (y - 3)² - 2   ⇒   y = 3 ± √(x + 2)

and y = 3 - √(x + 2) describe the bottom half of the red parabola.

Now we can set up the integrals.

Area of A:

\displaystyle \int_2^{(5+\sqrt5)/2} \left(\left(-\sqrt{y-1}\right) - \left((y-3)^2-2\right)\right) \, dy \\ ~~~~~~~~ = -\int_2^{(5+\sqrt5)/2} \left((y-3)^2 - 2 + \sqrt{y-1}\right) \, dy

Area of B:

\displaystyle \int_{-1}^{(-1+\sqrt5)/2} \left(\left(3-\sqrt{x+2}\right) - \left(x^2+1\right) \right) \, dx \\ ~~~~~~~~ = - \int_{-1}^{(-1+\sqrt5)/2} \left(x^2 - 2 + \sqrt{x+2}\right) \, dx

Alternatively, one can prove that the regions A and B are symmetric across the line y = x + 3, so we can simply pick one of these integrals and double it.

C. Computing the integrals, we find

area of A = 2/3

area of B = 2/3

and so the total area is 2/3 + 2/3 = 4/3.

6 0
2 years ago
Anybody have reading counts quiz info????
TiliK225 [7]

Answer:

doing this for 50 points

Explanation:

8 0
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