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Dima020 [189]
3 years ago
10

One of the requirements of your summer window-washing job is to provide yourself with all of the necessary supplies, including a

fourteen foot ladder. When you arrive at your first job, you place your ladder on the ground six feet from the base of the house and lean it towards a second story window, only to realize that the ladder doesn’t reach the window. Given the length of the ladder and its current position, what is one possible height of the second story window? (Hint: There is more than one correct answer.)
PLEASE HELP
Mathematics
1 answer:
Amanda [17]3 years ago
6 0
6,7,10and8

hope this helps you (:

if not plz let me know 

have a good day 
-denis 
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Solve this trinomial<br> Z^2 + z = -20
Naddik [55]

Answer:

your answer is a complex number making your question wrong

Step-by-step explanation:

First z²+z+20=0, just to make it a quadratic equation, so we can use the quadratric formula:

x=( -b±√b²-4ac)/2a

so to find a b and c we compare

YOUR QUESTION SHOULD BE Z² +Z-20=O.

4 0
3 years ago
What numbers go in the boxes?
oksian1 [2.3K]

For second one

Vertex is (-3,0)

  • Axis of symmetry=x=-3

There is only one x intercepts

  • Only one real root is -3

7 0
3 years ago
Read 2 more answers
if the store purchased a kitchen appliance for $42 and sold it for $58.80, what was the percent markup?
oksano4ka [1.4K]

Answer:

40%

Step-by-step explanation:

Percent markup = new price - original price/original price

Do the subtraction first.

58.80 - 42.00 = 16.80

Now do the division

16.8/42 = 0.40

Change the decimal to a percent by moving the decimal two place to the right.

0.40 = 40%

6 0
2 years ago
Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0. A. 3 B. 2
Zepler [3.9K]

Answer:

C. 0

Step-by-step explanation:

–4j^2 + 3j – 28 = 0

The discriminant is b^2-4ac  if >0 we have 2 real solutions

                                                   =0  we have 1 real solutions

                                                   <0 we have 2 imaginary solutions

a = -4, b =3  c = -28

b^2 -4ac

(3)^2 - 4(-4)*(-28)

9 - 16(28)

9 -448

This will be negative so we have two imaginary solutions.

Therefore we have 0 real solutions

5 0
4 years ago
PLZZ HELP URGENT
Mashcka [7]

Answer:

5x + 2x.....combine like terms..... = 7x

5x + 2x....subbing in 1                               7x - 1....subbing in 1

5(1) + 2(1) = 5 + 2 = 7                               7(1) - 1 = 7 - 1 = 6

5x + 2x...subbing in 2                                 7x - 1...subbing in 2

5(2) + 2(2) = 10 + 4 = 14                            7(2) - 1 = 14 - 1 = 13

5x + 2x...subbing in 3                                 7x - 1...subbing in 3

5(3) + 2(3) = 15 + 6 = 21                            7(3) - 1 = 21 - 1 = 20

5x + 2x...subbing in 4                                 7x - 1....subbing in 4

5(4) + 2(4) = 20 + 8 = 28                            7(4) - 1 = 28 - 1 = 27

5x + 2x...subbing in 5                                 7x - 1...subbing in 5

5(5) + 2(5) = 25 + 10 = 35                          7(5) - 1 = 35 - 1 = 34

5x + 2x result values are 1 more then 7x - 1 result values

there are no values that will make the 2 expressions equal....

because 5x + 2x = 7x......and the other one is 7x - 1......so the 7x - 1 values will always be 1 number less...because ur subtracting one

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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