Answer:
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Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0. A. 3 B. 2
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Answer:
-2<x<8
see below for graph
Step-by-step explanation:
First, we need to solve the inequality.
Inequality: |x-3|<5
Split into two equations:
x-3<5
x-3>-5 (notice how the sign is flipped when we make the number negative)
let's start with x-3<5
add 3 to both sides
x<8
now
x-3>-5
add 3 to both sides
x>-2
The graph is below
the intersection is the solution.
Notice how I made the maroon line go to the right- which shows that it's greater than (for x>-2) and the silver line go to the left, which shows that it's less than (for x<8)
the equation is -2<x<8
Hope this helps!
