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3 years ago

Number 58. Please HELP ME PLEASEEEE IM BEGGING YOU SMART ME

Mathematics

1 answer:

Fantom [35]3 years ago

3 0

Answer:0\6

Step-by-step explanation: There is not way you can pull a card out of a bag that does not have a number label if they are all labeled numbers

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Evaluate ( 1 2 )x^ 0 ,

Ymorist [56]

Answer:

i believe it would be 12

Step-by-step explanation:

Anything to the zero power is 1. One times 12 gives you your grand answer of 12!

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3 years ago

A television station allows 15 minutes of advertising each hour. How many 30 second (1/2 minute) commercials can be run in 1 day

AleksAgata [21]

(15 minutes/hour) x (1 spot / 1/2 minute) x (24 hour/day) = 720 spots/day

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3 years ago

Triangle KLM was dilated according to the rule

Anna35 [415]

Answer:

The statement that is true is;

The vertices of the image are closer to the origin than those of the pre-image

Step-by-step explanation:

The dilation rule is 0.75(x,y)= (0.75x, 0.75y)

K (-4,4)----------( 0.75*-4,0.75*4)-------K' (-3,3)

L (2,4)-----------(0.75*2,0.75*4)---------L' (1.5,3)

M (-2,2)----------(0.75*-2,0.75*2)--------M' (-1.5,1.5)

4 0

3 years ago

Read 2 more answers

Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.

sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

$\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ =I.

First, we have to identify the matrix I. As it was said, the matrix is the identiy matrix, which means

I = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

So, $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Isolating the X, we have

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ - $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Resolving:

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]$

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X= $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ ⁻¹· $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

$\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ · $\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a= $\frac{2}{11}$ ; b= $\frac{7}{33}$ ; c= $\frac{-1}{11}$ and d= $\frac{-3}{11}$ . Substituting:

X= $\left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11} \end{array}\right]$ · $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Multiplying the matrices, we have

X= $\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11} \end{array}\right]$

6 0

3 years ago

The SAT mathematics scores in the state of Florida for this year are approximately normally distributed with a mean of 500 and a

creativ13 [48]

99.7%

This is because the likelihood of a point being within 2 SDs of the mean is 99.7%.

7 0

3 years ago