Answer:
A) 1/5
Step-by-step explanation:
Points on the graph: (10, 2) and (20, 4)
Slope:
m=(y2-y1)/(x2-x1)
m=(4-2)/(20-10)
m= 2/10
m = 1/5
Answer:
We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm
Step-by-step explanation:
Sample Information:
Results:
41.8
40.9
42.1
41.2
40.5
41.1
42.6
40.6
From the table we get:
sample mean : x = 41.35
sample standard deviation s = 0.698
Hypothesis Test:
Null Hypothesis H₀ x = 41
Alternative Hypothesis Hₐ x > 41
The test is a one-tail test
If significance level is 0.01 and n = 8 we need to use t-student distribution
From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1
df = 7 t(c) = 2.998
To calculate t(s) = ( x - 41 ) / s/√n
t(s) = ( 41.35 - 41 ) / 0.698/√8
t(s) = 0.35 * 2.83/ 0.698
t(s) = 1.419
Comparing t(s) and t(c)
t(s) < t(c)
t(s) is in the acceptance region we accept H₀
If you Just divided -11u and 44 by -11 u equals 4
(3x+4)+(5x2-1)+(2x+6)
remove unnecessary parenthesis
3x+4+(5x2-1)+(2x+6)
3x+4+(10-1)+2x+6
subtract the numbers
3x+4+9+2x+6
collect the like terms
5x+4+4+9+6
5x+19
