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vaieri [72.5K]
3 years ago
6

In how many ways can 100 identical chairs be distributed to five different classrooms if the two largest rooms together receive

exactly half of the chairs
Mathematics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

There are 67626 ways of distributing the chairs.

Step-by-step explanation:

This is a combinatorial problem of balls and sticks. In order to represent a way of distributing n identical chairs to k classrooms we can align n balls and k-1 sticks. The first classroom will receive as many chairs as the amount of balls before the first stick. The second one will receive as many chairs as the amount of balls between the first and the second stick, the third classroom will receive the amount between the second and third stick and so on (if 2 sticks are one next to the other, then the respective classroom receives 0 chairs).

The total amount of ways to distribute n chairs to k classrooms as a result, is the total amount of ways to put k-1 sticks and n balls in a line. This can be represented by picking k-1 places for the sticks from n+k-1 places available; thus the cardinality will be the combinatorial number of n+k-1 with k-1, {n+k-1 \choose k-1} .

For the 2 largest classrooms we distribute n = 50 chairs. Here k = 2, thus the total amount of ways to distribute them is {50+2-1 \choose 2-1} = 51 .

For the 3 remaining classrooms (k=3) we need to distribute the remaining 50 chairs, here we have {50+3-1 \choose 3-1} = {52 \choose 2} = 1326 ways of making the distribution.

As a result, the total amount of possibilities for the chairs to be distributed is 51*1326 = 67626.

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A particular automatic sprinkler system has two different types of activation devices for each 3 sprinkler head. One type has a
zmey [24]

Answer:

There is an 85% probability that the sprinkler head will be activated.

Step-by-step explanation:

We have these following probabilities:

50% of the first sprinkler being triggered

90% of the first sprinkler being reliable

50% of the second sprinkler being triggered

80% of the second sprinkler being reliable.

What is the probability that the sprinkler head will be activated?

P = P_{1} + P_{2}

P_{1} is the probability of the first sprinkler being triggered and activated. So:

P_{1} = 0.5*0.9 = 0.45

P_{2} is the probability of the second sprinkler being triggered and activated. So:

P_{2} = 0.5*0.8 = 0.40

P = P_{1} + P_{2} = 0.40 + 0.45 = 0.85

There is an 85% probability that the sprinkler head will be activated.

6 0
3 years ago
How to solve 5a + c = -8a
sergey [27]

Solve for a:

5a+c=-8a\ \ \ |-c\\\\5a=-8a-c\ \ \ |+8a\\\\13a=-c\ \ \ |:13\\\\\boxed{a=-\dfrac{c}{13}}

Solve for c:

5a+c=-8a\ \ \ \ |-5a\\\\\boxed{c=-13a}

6 0
4 years ago
(03.02 MC)The number of pages that Ana, Hillary, Roger, and Juan can read in a day is shown below:
IgorLugansk [536]

Answer:

Juan

Step-by-step explanation:

The number of pages that Ana, Hillary, Roger, and Juan can read in a day is shown below:

For Ana

Ana read 15% of her 46-page book.

= 15% × 46 pages

= 6.9 pages

For Hillary

Hillary read 11% of her 72-page book.

= 11% × 72 pages

= 7.92 pages

For Roger

Roger read 12% of his 68-page book.

= 12% × 68 pages

= 8.16 pages

For Juan

Juan read 14% of his 69-page book.

= 14% × 69 pages

= 9.66 pages

The person who can read greatest number of pages in a day also means the person who read the highest number of pages in a day.

From the calculation above, that person in JUAN because she can read 9.66 pages of her book in one day.

5 0
3 years ago
Please help and tell me why u got that answer, I will mark brainliest
gregori [183]
The answer is C

i think so
4 0
3 years ago
Pls pls help me I will mark you brainest
Musya8 [376]

Answer:

It would be 125m^2

Step-by-step explanation:

17*10=170

170/2=85

8*10=80

80/2=40

85+40=125

7 0
2 years ago
Read 2 more answers
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