Answer:
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Answer:
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Step-by-step explanation:
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You need to include the radius.
Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
$21,000-16%
16% of $21,000 is $3,360
$21,000-$3,360=$17,640
1st year would be $17,640
16% of $17,640 is $2,822
$17,640-$2,822 is $14,817
2nd year would be $14,817
16% of $14,817 is $2,370
$14,817-$2,370=$12,446
3rd year would be $12,446
$12,446 rounded would be $12,447
So A) $12,447
Hope this helps out :)
