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3 years ago

WILL MARK BRAINLEIST FOR TRUE ANSWERS!!! 7th Grade Math

Mathematics

1 answer:

cestrela7 [59]3 years ago

4 0

Answer:

330 hope this helps you

Step-by-step explanation:

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Jared puts dollars in a jar. the following week he puts 2 more dollars in the jar. for each of the following six weeks, Jared co

djyliett [7]

Answer:

ur answer would be lineaer nothing is changing and everyone is decreasing within a pattern

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2 years ago

How much less is -2than 3

Law Incorporation [45]

-2 is 5 less than 3

hope this helps

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3 years ago

Read 2 more answers

Please help with both problems

erica [24]

Okay so i cant figure out the first one, but the second one looks like -7:3

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2 years ago

Determine the standard deviation of the data below. (1, 2, 3, 4, 5)

Burka [1]

Answer:

$\sqrt{2}$ or 1.414

Step-by-step explanation:

1) Find the mean. 1+2+3+4+5 = 15. 15/5= 3

2) For each data point, find the square of its distance to the mean. (4, 1, 0, 1, 4)

3) Sum the values from Step 2. 10

4) Divide by the number of data points. 10/5= 2

5) Take the square root. $\sqrt{2}$

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2 years ago

At the beginning of an environmental study, a forest covered an area of 1500 km2 . Since then, this area has decreased by 9.8% e

fredd [130]

Answer:

$A(t)=(0.902)^t \cdot 1500$ $[km^2]$

Step-by-step explanation:

In this problem, the initial area of the forest at time t = 0 is

$A_0 = 1500 km^2$

After every year, the area of the forest decreases by 9.8%: this means that the area of the forest every year is (100%-9.8%=90.2%) of the area of the previous year.

So for instance, after 1 year, the area is

$A_1 = A_0 \cdot \frac{90.2}{100}=0.902 A_0$

After 2 years,

$A_2=0.902 A_1 = 0.902(0.902A_0)=(0.902)^2 A_0$

And so on. So, after t years, the area of the forest will be

$A(t)=(0.902)^t A_0$

And by substituting the value of A0, we can find an explicit expression:

$A(t)=(0.902)^t \cdot 1500$ $[km^2]$

8 0

3 years ago

**WILL MARK BRAINLEIST FOR TRUE ANSWERS!!!** 7th Grade Math

WILL MARK BRAINLEIST FOR TRUE ANSWERS!!! 7th Grade Math