The area of the surface of the pool is 7322.64 m².
<h3>What is Area of rectangle?</h3>
The area of rectangle is product of length and its breadth.
i.e., length * breadth
Given: Length = 100 m, Width = 52 m and Diameter = 52 m
Area of rectangle,
= 100 × 52
= 5200 m²
Now,
Area of semicircle = 1/2 × πr²
=1/2 × 3.14 × 26²
= 1061.32 m²
Hence, area of the surface of the pool is
= 1061.32 + 1061.32 + 5200
= 7322.64 m²
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2 Dewey you can still go to get
For the diagonal of the floor:
20^2 + 48^2= c^2
400+2304= c^2
c=52
For the diagonal of the cube:
52^2 + 10^2 = c^2
2704+100=c^2
c=52.95
Rounded= 53
Tell me if this helps!!!