Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Let the no. be x
A/Q
=> 36 × x /100 = 18
=> x = 18 × 100 / 36
=> x = 50
Answer:
3/5
Step-by-step explanation:
1/2=2/4
2+1=3
1+4=5
3/5
We know that
[surface area for a rectangular prism with a square base ]=2*s²+4*s*h
2*s²----> Is the surface area of the bases
4*s*h---> is the lateral area
s=2 units
h=4 units
[surface area for a rectangular prism with a square base ]=2*2²+4*2*4
surface area=8+32----> 40 units²
the answer is
40 units²
Let James be x years old
Joe = 10 + x
After 8 years
18 + x = 3(x)
18 + x = 3x
18 = 2x
x = 9
Joe is 19
James is 9
