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Natalija [7]
3 years ago
5

In this figure, sin(a) = 23

Mathematics
1 answer:
WITCHER [35]3 years ago
4 0
a and b are complementary, or b=\dfrac\pi2-a. So

\cos b=\cos\left(\dfrac\pi2-a\right)=\sin a

and so \cos b=\dfrac23.
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(a) Estimate the area under the graph of f(x) = 2 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right end
nirvana33 [79]
  <span>first, we are going to define variables as the following: 

a = 0 
a = π/2 
n = 4 rectangles 

Δx = [ b - a ] / n ------>Δx = [ π/2 - 0 ] / 4 = π/8 

right endpoints : 
sum( seq( 4 cos(x) * π/8 , x , 0+π/8 , π/2 , π/8 ) ) = 3.163065 underestimate 

left endpoints: 
sum( seq( 4 cos(x) * π/8 , x , 0 , π/2-(π/8) , π/8 ) ) = 4.733861 overestimate 

the reason because the actual estimate by integral as the following: 
π/2 
∫ 4cos(x) dx = 4 
0</span>
8 0
3 years ago
On reading at An artic research station showed that the temperature was -35 C. What is this temperature in degrees Fahrenheit?
Travka [436]

the answer is -22 F

5 0
3 years ago
A cricket team has a 0.25 chance of losing
Westkost [7]

Answer:

a) 0.125

b) 0.015635

c) 0.00000095367431640625‬

Step-by-step explanation:

a) 0.25^2 = 0.125

b) 0.25^3 = 0.015625

c) 0.25^{10} = 0.00000095367431640625\\\\

8 0
3 years ago
Read 2 more answers
PLEASE HELP WORTH 99 POINTS AND CORRECT ANSWER WILL GET BRAINLIEST
Soloha48 [4]

Hello!

I believe the answers are:

A) The vertex is (1, −6)

C) The graph has a minimum.

I hope it helps!

7 0
3 years ago
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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
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