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Natalija [7]
3 years ago
5

In this figure, sin(a) = 23

Mathematics
1 answer:
WITCHER [35]3 years ago
4 0
a and b are complementary, or b=\dfrac\pi2-a. So

\cos b=\cos\left(\dfrac\pi2-a\right)=\sin a

and so \cos b=\dfrac23.
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Solve this system of equation using substitution y=2x-4 x+2y=10
Vladimir79 [104]
Y=2x-4
X+2y=10

Put y into the x equation
X+2(2x-4) =10

Expand and simplify
X+4x-8=10
5x-8 =10
5x=10+8
5x=18
X=18/5

Insert x into the original equation to get y
Y=2x-4
Y=2(18/5)-4
Y=16/5
4 0
2 years ago
A random sample of 50 bottles is selected from the production line of a large manufacturing company. The mean weight of the cont
andrew11 [14]

Answer:

The population is all bottles in the production line and the sample is the 50 bottles that were selected.

Step-by-step explanation:

Edge 2020

4 0
3 years ago
Dddddddddddddddddddddddd
Ierofanga [76]

Answer:

dddddddddddddddddddddddd could be rewritten as d^24 because d*d*d*d*d*d*d... = d^24

Step-by-step explanation:

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4 0
3 years ago
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154 - 4(1 + 6m) + 6m​
polet [3.4K]

Answer:

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Thats the correct answer

5 0
3 years ago
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
3 years ago
Read 2 more answers
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