2 answers:
3x^2 – 5x – 12 = (3x+4<span>)</span>(x-3)
x^2 -9 = (x-3<span>)</span>^2
<span>8x^3+ 12x^2 - 2x - 3 = (4x^2 -
1)(2x + 3)
</span>12x^2 +16x -3= (6x - 1)(2x + 3)
x^2 + 8x - 9= (x + 9<span>)</span>(x - 1) (I <span>can not</span> see
who it can all be positive<span> ;</span>_;<span> )</span>
<span>3(x + y) + a(x + y)= (3x + 3y) + (ax + ay)</span>
7. 3x² - 5x - 12
3x² - 9x + 4x - 12
(3x + 4)(x - 3)
8. x² - 9
x² + 3x - 3x - 9
(x - 3)(x + 3)
9. 8x³ + 12x² - 2x - 3
(8x³ + 12x² - 2x - 3)
(4x² - 1)(2x + 3)
10. 12x² + 16x - 3
12x² + 18x - 2x - 3
(6x - 1)(2x + 3)
11. x² + 8x + 9
(x² + 9x - x + (-9))
(x - 1)(x + (-9))
Extra Credit: 3(x + y) + a(x + y)
3(x) + 3(y) + a(x) + a(y)
3x + 3y + ax + ay
3x + ax + 3y + ay
(3 + a)x + (3 + a)y
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The answer to your question is A.
Answer:
-3+1/5
Step-by-step explanation:
Answer:
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Hope you got your answer.
Cut only to ends of the triangle off then it will have a pentagon with the uncut shape
C) 12V2
12^2 + 12^2 = c^2
144 + 144 = 288
V288 = 12V2