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stepladder [879]
3 years ago
9

Perform the indicated operations; reduce the answer to lowest terms.

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
5 0

d. LCD = 30 divide numerator into 30

20/30- 18/30 =2/30 simplify divide by 2

1/15

e. multiply bottom and top

4/10×3/7 =12/70 simplify divide by 2

6/35

f.multiply bottom and top

1/6×6/15 =6/90 simplify divide by 6

1/15

g.keep the first one,change the sign, flip the second one(kcf)

1/8×9/4 =9/32

h.same thing as g.

1/5×4/3 =4/15

Misha Larkins [42]3 years ago
4 0

d.

\frac{1}{15}

e.

\frac{6}{35}

f.

\frac{1}{15}

g.

\frac{9}{32}

h.

\frac{4}{15}

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The table below shows the temperature in degrees for eight consecutive days as well as the respective number of ice cream cones
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We have to find the equation of least squares regression line in order to find the number of ice cream cones that the shopkeeper to sell if the temperature is 106 degrees. We can use excel regression data analysis tool to find the equation of the regression line. The excel output is attached here.

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6 0
3 years ago
The line integral of (2x+9z) ds where the curve is given by the parametric equations x=t, y=t^2, z=t^3 for t between 0 and 1. Pl
Naya [18.7K]
Let r = (t,t^2,t^3)

Then r' = (1, 2t, 3t^2)

General Line integral is:
\int_a^b f(r) |r'| dt

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector \sqrt{(x')^2 + (y')^2 + (z')^2}

\int_0^1 (2t+9t^3) \sqrt{1+4t^2 +9t^4} dt

Fortunately, this simplifies nicely with a 'u' substitution.

Let u = 1+4t^2 +9t^4

du = 8t + 36t^3  dt

\int_0^1 \frac{2t+9t^3}{8t+36t^3} \sqrt{u}  du \\  \\ \int_0^1 \frac{2t+9t^3}{4(2t+9t^3)} \sqrt{u}  du \\  \\  \frac{1}{4} \int_0^1 \sqrt{u}  du

After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
=\frac{1}{4} |_0^1 (\frac{2}{3}) (1+4t^2 +9t^4)^{3/2} \\  \\ =\frac{1}{6} (14^{3/2} - 1)
7 0
3 years ago
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