Answer:
30-5×2 of 3+(19-3) ÷8
Step-by-step explanation:
30-5×6+(19-3)÷8
30-5×6+16÷8
30-30+8
38-30
8
Answer:
It might be 8
Step-by-step explanation:
40-32=8
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer: x = 16
Step-by-step explanation:
X-6 = 10
X = 10 + 6
X = 16
<h3>
Answer: t = 7</h3>
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Explanation:
If we replace every copy of x with t, then we go from this
F(x) = 3x+5
to this
F(t) = 3t + 5
All we've done really is change the letter. We still are dealing with a variable. We're told that F(t) is equal to 26, which would allow us to replace the "F(t)" with "26" in the second equation above.
So we now have the equation 26 = 3t+5 which is the same as 3t+5 = 26
Let's solve for t
3t+5 = 26
3t = 26-5 .... subtract 5 from both sides
3t = 21
t = 21/3 .... divide both sides by 3
t = 7 is the answer
Now note that...
F(t) = 3t + 5
F(7) = 3*7 + 5 .... replace t with 7
F(7) = 21 + 5
F(7) = 26
This means we got F(t) = 26 when t = 7
It's the same as saying x = 7 leads to F(x) = 26.
This helps confirm we have the correct answer.
