<span>The range of Cos(x) is [-1,1]. Therefore the range of ln(Cos(x)) will be the image of [-1,1] using the natural log function. However, the domain of ln(x) is (0,infinity) and the log function is strictly increasing with vertical asymptote at "x=0". Therefore, the range of ln(Cos(x)) will be:
(- infinity, ln(1) ] = (-infinity, 0] !</span><span>so its true </span>
Answer:
197.50
Step-by-step explanation:
Answer:
68%
Step-by-step explanation:
The mean is 32 minutes, and the standard deviation is 4 minutes.
28 is 1 standard deviation below the mean, and 36 is 1 standard deviation above the mean.
According to the empirical rule, 68% of a normal distribution is between -1 and 1 standard deviations. 95% is between -2 and 2 standard deviations. 99.5% is between -3 and 3 standard deviations.
So the answer is 68%.
The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0
Thus, the equation of the trend line, in variables K and J, is
K = 2J + 28
Gosh, I've done this problem before. Let's start with 13. In this problem, we're basically just skip counting. For example, in the roses row, in the second bouquet, we know we have to add 4 more flowers, so we can document 8. Continue to skip count for both. For 15, we would have about 96 more movie posters remaining, making our ratio 96:x. So, 96:x = 120:100. Therefore, x would equal 80- as 96:80 equals 120:100. If she needs 80 and already had 100, she should sell 20 posters. Hope this helped.