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3 years ago

:) The bus fare of 12 passengers is Rs 540. If the fare is increased by Rs 5 per

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

4 0

Answer:

<h2>15 passengers </h2>

Step-by-step explanation:

Original price,

Fare for 12 passengers = Rs 540

Fare for 1 passenger = $\frac{540}{12} = 45$

Increased price,

Fare for 1 passenger = 45 + 5 = Rs 50

Let fare for X passengers be 750

$x \times 50 = 750$

$x = \frac{750}{50}$

$x = 15$

Hence, 15 passengers can travel for Rs 750.

Hope this helps...

Good luck on your assignment..

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3 years ago

16/x = 2/7 cross multiplication

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Answer:

x=56

Step-by-step explanation:

16 x 7= x * 2

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8 0

2 years ago

A jar containing only dimes and quarters contains a total of 54 coins. The value of all the coins in the jar is $9.15. Solve by

Paladinen [302]

Answer: the jar contains 29 dimes and 25 quarters.

Step-by-step explanation:

The worth of a dime is 10 cents. Converting to dollars, it becomes

10/100 = $0.1

The worth of a quarters is 25 cents. Converting to dollars, it becomes

25/100 = $0.25

Let x represent the number of dimes contained in the jar.

Let y represent the number of quarters contained in the jar.

A jar containing only dimes and quarters contains a total of 54 coins.. This means that

x + y = 54

The value of all the coins in the jar is $9.15. This means that

0.1x + 0.25y = 9.15 - - - - - - - - - - - 1

Substituting x = 54 - y into equation 1, it becomes

0.1(54 - y) + 0.25y = 9.15

5.4 - 0.1y + 0.25y = 9.15

- 0.1y + 0.25y = 9.15 - 5.4

0.15y = 3.75

y = 3.75/0.15 = 25

x = 54 - y = 54 - 25

x = 29

7 0

2 years ago

2.5 hours is equal to 2 hours and 30 minutes <br> True or false<br>

Feliz [49]

Answer:

True because 1/2 an hour is 30 minutes.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d

gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

Step-by-step explanation:

Evaluate:

$\dfrac{b-3a}{bc^{2}-d}$

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\$

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1$

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

6 0

3 years ago