Area of a sector: 1/2r^2 theta
Need theta
Let x be theta for now
42.25 pi = 1/2r^2x
84.5pi = r^2x
84.5pi = 169x
x = 84.5pi/169 = roughly 1.57 in radians
Radians => degrees is 1.57 * 180/pi or roughly 90.
= 4
= -6
HOPE THIS HELP ^_^
is there any answers or no?
Answer:
Step-by-step explanation:
=7 (1+11+111+1111......n)
=7/9 (9+99+999+9999....n)
=7/9 ((10-1)+(10^2-1)+(10^3-1)+....n)
=7/9 ((10+10^2+10^3...n)-(1+1+1+1.....n))
=7/9 ((10 (10^n-1)/(10-1))-n)
Answer:
The measures of each would be:
105° and 75°
Step-by-step explanation:
Supplementary angles are two angles whose measures sum up to 180° or they form a straight line.
So if an angle measures 30° less than the measure of its supplementary, it wold mean that both angles together is equal to 180°.
∠1 = x
∠2 = x-30°
∠1 + ∠2 = 180°
So here we plug in our equations:
∠1 + ∠2 = 180°
x + x - 30° = 180°
2x - 30° = 180°
We solve for the x then:
Add 30° on both sides of the equation:
2x - 30° + 30° = 180° + 30°
2x = 210°
Divide both sides by 2:
2x/2 = 210°/2
x = 105°
∠1 = 105°
Now we solve for the second angle:
∠1 + ∠2 = 180°
105° + ∠2 = 180°
Subtract 105° from both sides of the equation:
105° + ∠2 - 105° = 180° - 105°
∠2 = 75°
