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Mademuasel [1]
4 years ago
8

Please help me in this question.Easy question.

Mathematics
1 answer:
Zanzabum4 years ago
5 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

You can use Pythagoras theorem as it is a right angle

a^2 + b^2 = c^2

where 'c' is the hypotenuse

Rearrange this to find a side length

c^2 - a^2 = b^2

where 'b' is the missing length

10^2 - 8^2 = b^2

100 - 64 = b^2

b^2 = 36

Square root this to get the answer

b = 6cm

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

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For each sequence, find the first 4 terms and the 10th term.<br> A) n+5<br> B)2n-1
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Answer:

see explanation

Step-by-step explanation:

(a)

To find the first 4 terms substitute n = 1, 2, 3, 4 into the n th term formula.

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a₃ = 3 + 5 = 8

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(b)

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5 0
3 years ago
Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the
nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}

Where :

m = mass of the oebjct in motion

m_o = mass of the object when at rest

v = velocity of a moving object

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We have :

1) Mass of the Dave = m_o=66 kg

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Mass of the Dave when moving at 90% of the speed of light:

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Mass of the Dave when moving at 99% of the speed of light:

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3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

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m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = m_o=66 kg

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v=2.973\times 10^8 m/s

Dave should be moving at speed of 2.973\times 10^8 m/s.

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