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lesya [120]
3 years ago
6

Can anyone pls pls pls help me in dis pls I will mark u as brainliest!!!!

Mathematics
1 answer:
motikmotik3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

Infinite Solutions:

1. \:\:n=n\\\\2.\:\:y\cdot -6\cdot -3=2\cdot y\cdot 9\\\\3. \:\:5-9+3x=-10+6+3x\\\\4. \:\:2t+6=2(t+3)\\

No Solutions:

1. \:\:v+2=v-2\\\\2.\:\:\frac{1}{4}\left(20d+4\right)=5d\\\\3.\:\:3\left(n+1\right)=3n+1\\\\4.\:\:\frac{1}{2}+x=\frac{1}{3}+x

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Answer:

C. (5x^3-7)(2x^2+1)

Step-by-step explanation:

Given expression is,

10x^5+5x^3-14x^2-7

=10x^5-14x^2 + 5x^3 - 7  (By the commutative property)

=2x^2(5x^3-7)+5x^3-7     (Taking 2x^3 common from first two terms )

=(5x^3-7)(2x^2+1)      (Taking 5x^3-7 common from both terms)

\implies 10x^5+5x^3-14x^2-7=(5x^3-7)(2x^2+1)

Hence, Option C is correct

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3 years ago
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Doss [256]
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Step-by-step explanation:

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