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lesya [120]
4 years ago
6

Can anyone pls pls pls help me in dis pls I will mark u as brainliest!!!!

Mathematics
1 answer:
motikmotik4 years ago
5 0

Answer:

See below.

Step-by-step explanation:

Infinite Solutions:

1. \:\:n=n\\\\2.\:\:y\cdot -6\cdot -3=2\cdot y\cdot 9\\\\3. \:\:5-9+3x=-10+6+3x\\\\4. \:\:2t+6=2(t+3)\\

No Solutions:

1. \:\:v+2=v-2\\\\2.\:\:\frac{1}{4}\left(20d+4\right)=5d\\\\3.\:\:3\left(n+1\right)=3n+1\\\\4.\:\:\frac{1}{2}+x=\frac{1}{3}+x

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Solve the problem. Give the equation using x as the variable, and give the answer.
Korolek [52]

Answer:

The equation is     8x+7=112

Step-by-step explanation:

the answer is 13.125

this is what i got. i am sorry if it is wrong.

4 0
3 years ago
Someone please answer this for me
Alenkinab [10]

Diameter 4m, radius is half,

Radius Answer: 2  m

Volume is

V = (4/3)πr³ = (4/3)π 2³ = (4/3)π(8) = (32/3) π

Answer: 32/3            (× π cubic meters)

4 0
3 years ago
Please help me on this
KATRIN_1 [288]

Answer:

C 7 times 5 plus 7 times 4 is the answer

8 0
3 years ago
Read 2 more answers
Simple math but I can't seem to understand it: x+y=2 becomes y=2-x, in order to find slope and y intercept y=mx+b The result bec
IgorLugansk [536]

Answer:

See below.

Step-by-step explanation:

So we started off with the equation:

x+y=2

And we subtracted x from both sides to acquire:

y=2-x

Now, this is essentially slope-intercept form. Recall that the slope-intercept form is:

y=mx+b

Where m is the slope and b is the y-intercept.

If we rearrange our equation:

y=2-x\\y=-x+2

And put some parentheses:

y=(-1)x+(2)

We can see that this is indeed slope-intercept form.

And we can see that m is -1 and b is 2.

In other words, the slope is -1 and the y-intercept is 2.

3 0
4 years ago
Read 2 more answers
A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.
zzz [600]

Answer:

CI=(66.54,78.46)                                  

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , \bar{X}=72.5\% , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}

From the t-table with 9 degree of freedom for \frac{\alpha}{2}=0.005

t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}

t_{n-1,\frac{\alpha}{2}}=3.250

The 99% confidence interval is given by,

CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}

CI=72.5 \pm 5.96

CI=(72.5+5.96),(72.5-5.96)

CI=(66.54,78.46)

8 0
3 years ago
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