C=10pi
C=2(r)pi so r=5
A=pi(r)^2
so A=pi(5)^2
A=25pi
We have been given an equation
. We are asked to solve our given equation for x.
First of all, we will separate expression with x on one side of equation. We can do it by subtracting 5 from both sides of equation.


Now we will switch the sides as:

Now we will divide both sides by
as:


Therefore, the value of x would be
.
18. -4, 4
19. -38, 38
20. -260, 260
21. -4092, 4092.
I might be wrong but...
Answer:
Impossible
Step-by-step explanation:
In 5x^2-4x+3=0, standard form, substitute these values in the quadratic formula:
a = 5; b = -4; c = 3
The quadratic formula is 
(ignore the weird capital A)
Substitute a b and c:

Simplify:

Because
is the square root of a negative number, the answer would be imaginary.
Therefore, there are not solutions to this equation.
A solution is the same as the roots or zeroes, where the graph would cross the x-axis when graphed.
The graph never meets the x-axis. It looks like this: