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valentina_108 [34]

4 years ago

12

Which equality represents the proportion $10 is to 15 cans as $30 is to $45 cans?

1 answer:

Sladkaya [172]4 years ago

5 0

Answer:

I'm guessing it's C because it's the only one that looks right

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Which of the following describes the function −x3 + 5?

algol13

Answer:

The correct choice is C

Step-by-step explanation:

The given function is:

$-x^3+5$

The degree of this function is odd so the function will rise at one end and fall on the other end.

Since the coefficient of the leading term is negative, the graph of the function will rise at the left and fall on the right.

The correct answer is option C.

4 0

3 years ago

8. Find the distance between M(-2, 3) and N(8,2). number 8 please

Ilya [14]

Answer:

The answer is $\sqrt{x} 101$

Step-by-step explanation:

3 0

3 years ago

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What is the cube root of 27x^18

kotegsom [21]

Answer:

∛27 x 18

= ∛ 3 x 3 x 3 x 3 x 3 x 2

= 3 ∛18

4 0

3 years ago

BRAINLIEST LOL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

egoroff_w [7]

Answer:

B

Step-by-step explanation:

4 0

3 years ago

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solve the following quadratic equation using the quadratic formula and then choose the correct solution set 8x2-6x+1=0

MrRa [10]

Answer:

The solutions to the quadratic equation using the quadratic formula will be:

$x=\frac{1}{2},\:x=\frac{1}{4}$

Step-by-step explanation:

Given the equation

$8x^2-6x+1=0$

solving with the quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=8,\:b=-6,\:c=1$

$x_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:8\cdot \:1}}{2\cdot \:8}$

as

$\sqrt{\left(-6\right)^2-4\cdot \:8\cdot \:1}=2$

so

$x_{1,\:2}=\frac{-\left(-6\right)\pm \:2}{2\cdot \:8}$

Separating the solution

$x_1=\frac{-\left(-6\right)+2}{2\cdot \:8},\:x_2=\frac{-\left(-6\right)-2}{2\cdot \:8}$

solving

$x_1=\frac{-\left(-6\right)+2}{2\cdot \:\:8}$

$=\frac{6+2}{2\cdot \:8}$

$=\frac{8}{16}$

$=\frac{1}{2}$

and

$x_2=\frac{-\left(-6\right)-2}{2\cdot \:8}$

$=\frac{6-2}{2\cdot \:\:\:8}$

$=\frac{4}{16}$

$=\frac{1}{4}$

Therefore, the solutions to the quadratic equation using the quadratic formula will be:

$x=\frac{1}{2},\:x=\frac{1}{4}$

4 0

3 years ago

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