Answer:
y=x+2
Step-by-step explanation:
1) Solve for m using the equation m=y2-y1/x2-x1 by plugging in any 2 coordinates from the table
2) After getting m, which is 1, you can solve for b by plugging in another coordinate. For example,the coordinate (1,3): 3=(1)1+b
3) You then solve for b, which is 2
Answer: y=x+2
Answer:
hey im not actually here to help you, i just need points. thanks for the points
Step-by-step explanation:
The given equation is-
First, we move the independent term to the other side.
Now, we have to use the quadratic equation to find the solutions.-
![x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Where, a = 1, b = -10, and c = 34.
Replacing these values in the formula, we have.
![\begin{gathered} x_{1,2}=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(1)(34)}}{2(1)} \\ x_{1,2}=\frac{10\pm\sqrt[]{100-136}}{2}=\frac{10\pm\sqrt[]{-36}}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x_%7B1%2C2%7D%3D%5Cfrac%7B-%28-10%29%5Cpm%5Csqrt%5B%5D%7B%28-10%29%5E2-4%281%29%2834%29%7D%7D%7B2%281%29%7D%20%5C%5C%20x_%7B1%2C2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B100-136%7D%7D%7B2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B-36%7D%7D%7B2%7D%20%5Cend%7Bgathered%7D)
But, there's no square root of -36 because it's a negative. To solve this issue, we use complex numbers that way, we would have solutions.
![x_{1,2}=\frac{10\pm\sqrt[]{36}i}{2}=\frac{10\pm6i}{2}=5\pm3i](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B36%7Di%7D%7B2%7D%3D%5Cfrac%7B10%5Cpm6i%7D%7B2%7D%3D5%5Cpm3i)
<h2>Therefore, the solutions are</h2>
The right answer is B.
Find the first semicircle area
Area semicircle can be determined by dividing the full area of circle by 2.
The first semicircle radius is 5 cm
semicircle area = 1/2 circle area
semicircle area = 1/2 × π × r²
semicircle area = 1/2 × 3.14 × 5²
semicircle area = 1/2 × 3.14 × 25
semicircle area = 39.25 cm²
Find the second semicircle area
Because the dimension of the second semicircle is congruent to the first semicircle, they have similar area measurement, 39.25 cm².
Find the quarter circle area
The area of quarter circle can be determined by dividing the full area of a circle by 4.
q circle = 1/4 × area of circle
q circle = 1/4 × π × r²
q circle = 1/4 × 3.14 × 10²
q circle = 1/4 × 314
q circle = 78.5 cm²
To find the entire area, add the area above together
area = first semicircle + second semicircle + q circle
area = 39.25 + 39.25 + 78.5
area = 157
The area of shaded region is 157 cm²
The answer is c 19
38/2=19
Step-by-step explanation
