Factor out the greatest common monomial: 8x3 y2 - 12x2 y3 + 28x2 y

1 answer:

3 0

Yes xy(8x2 y - 12xy2 - 7x) is the number you would use for the equation of the formula to figure out the mathematical term you would perhaps use if the values located inside the equation were numerous.

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3a^2 (ab^2+b^2)=<br> How much

kiruha [24]

Answer is 3a²b (a + b)

Step-by-step explanation:

Step 1: Find 3a² (ab²+b²)

⇒ 3a² (ab²+b²) = 3a³b + 3a²b² = 3a²b (a + b)

8 0

3 years ago

Answer this as soon as possible

kenny6666 [7]

Answer:

21+3t

If really want equation answer it would be -7 but it simplifying. :)

Step-by-step explanation:

6(4+t)-3(t+1)

Simplify parenthesis first.

24+6t-3t-3

Simplify like terms

24-3+6t-3t

21+3t

5 0

3 years ago

We were never taught this in class, and I understand it, kind of... but i'm just confused with everything.

GaryK [48]

$\bf \cfrac{x^3y}{xy^5}\cdot \cfrac{x^2y^9}{x^8}\implies \cfrac{x^3x^2y^1y^9}{x^1x^8y^5}
\\ \quad \\
\textit{now, using exponent rules, same base, different exponent}
\\ \quad \\
\cfrac{x^{3+2}y^{1+9}}{x^{1+8}y^5}\implies \cfrac{x^5y^{10}}{x^9y^5}\\
----------------------------\\$ $\bf \textit{now, keep in mind that}
\\ \quad \\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad

\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
% negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 

\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}}
\\ \quad \\
thus\\
----------------------------\\
$ $\bf \cfrac{x^5y^{10}}{x^9y^5}\implies \cfrac{x^5y^{10}}{1}\cdot \cfrac{1}{x^9}\cdot \cfrac{1}{y^5}\implies x^5y^{10}\cdot x^{\boxed{-9}}\cdot y^{\boxed{-5}}
\\ \quad \\
x^5x^{-9}y^{10}y^{-5}\implies x^{5-9}y^{10-5}\implies x^{-4}y^5
\\ \quad \\
\cfrac{1}{x^{\boxed{4}}}\cdot \cfrac{y^5}{1}\implies \cfrac{y^5}{x^4}$

8 0

3 years ago

What is ¼(2.5 + c) (8) = 11

artcher [175]

The answer is this c= 3

8 0

3 years ago

Read 2 more answers

Answer number 20 plz (geometry)

zhenek [66]

Same homework I have.super hard!!!

4 0

3 years ago