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GrogVix [38]
3 years ago
7

The area of a trapezium is 34 cm and the length one of its parallel side is

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0

Answer:

6.6 cm.

Step-by-step explanation:

The area of a trapezium A = (h/2)(a + b)    where h = the height, a and b are the length of the parallel sides.

So substituting the given values in this formula:

34 = (4/2)(10.4 + b)

34 =  2(10.4 + b

34 = 20.8 + 2b

2b = 34 - 20.8 = 13.2

b = 6.6 cm.

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djverab [1.8K]

I'll assume the ODE is

y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}

Solve the homogeneous ODE,

y'' - 3y' + 2y = 0

The characteristic equation

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has roots at r=1 and r=2. Then the characteristic solution is

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For nonhomogeneous ODE (1),

y'' - 3y' + 2y = e^x

consider the ansatz particular solution

y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x

Substituting this into (1) gives

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y'' - 3y' + 2y = e^{2x}

take the ansatz

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take the ansatz

y = ce^{-x} \implies y' = -ce^{-x} \implies y'' = ce^{-x}

and solve for c.

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\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}

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1 year ago
Raymond can type 40 words each minute. How many words can he type in 8 minutes?
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Answer:

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2 years ago
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An inheritance of $40,000 is divided among three investments yielding $3,500 in interest per year. The interest rates for the th
a_sh-v [17]

Answer:

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given,

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     z = 16000 - 5000 = $ 11,000

the investment by each

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