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GrogVix [38]
3 years ago
7

The area of a trapezium is 34 cm and the length one of its parallel side is

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0

Answer:

6.6 cm.

Step-by-step explanation:

The area of a trapezium A = (h/2)(a + b)    where h = the height, a and b are the length of the parallel sides.

So substituting the given values in this formula:

34 = (4/2)(10.4 + b)

34 =  2(10.4 + b

34 = 20.8 + 2b

2b = 34 - 20.8 = 13.2

b = 6.6 cm.

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Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
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a square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the
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Answer:

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Step-by-step explanation:

Square field has a side = 150 m

Area of the field = (Side)²

                           = (150)²

                           = 22500 m²

Length of the park with road around the field = 150 + 2×(width of the road)

                                                                            = 150 + (2×5)

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Similarly, width of the park with road around the field = 160 m

Area of the park with road = (Side)²

                                            = (160)²

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Area of road = Area of the park with road - Area of the park

                     = 25600 - 22500

                     = 3100 m²

Since, cost of constructing the road = 250 rupees per square meter

Cost to construct the road with the given area = 250 × 3100

                                                                              = 775000 rupees

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