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Blababa [14]
3 years ago
9

For each function, do the following: a) state the name of the function, b) identify the independent and dependent variable, c) i

dentify the rule that assigns exactly one output to the very input, and d) evaluate the function for the given input value.

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0
<h2>Hello</h2>

The answers are:

a) The name of the function is h, and it's an Exponential Function.

b) Independent variable : x , dependent variable : h(x)/y

c) The rule that assigns exactly one output to the very input is called "function".

d) h(3)=3^{3}-7=27-7=20

<h2> Why?</h2><h2 />

Usually, the name of a function (h(x)) is the letter that is out of the parentheses. For this  particular case,  the name of the function is "h", and it's an Exponential Function.

The independent variable of a function is the variable we assign the different values, so, for this case, the independent variable is designated with the letter "x".

The dependent variable is the function itself (h(x)), it's also called "y", it's called "dependent" variable because its values will always depend on the "independent variable".

A function is the rule that states that there is exactly one output (range value) to the very input (domain value).  A function only exists when there is exactly one output value (range) for each input (domain), if there is more than one output for each input, the function does not exist.

Evaluating a function consists of assign values to the independent variable(x), hence:

h(3)=3^{3}-7=27-7=20

Have a nice day!

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Answer:

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Step-by-step explanation:

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This question is kind of ambigous and I'll make the assumption that there is no payment at time 0

\begin{gathered}175000=x\frac{(1+.029)^{2*18}-1}{.029}\\x=2821.511\end{gathered}

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−1

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interested earned:

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2.)

Same assumption as question 1 (there is no payment at time 0)

effective rate: .063/12= .00525

400(\frac{(1+.00525)^{60}-1}{.00525})=28124.24400(

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60

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Interest earned: 28124-400*60=4124.24

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Answer:

Step-by-step explanation:

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~~~~~~~~~~~~~~

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