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GuDViN [60]
3 years ago
5

Two boys divided $3.36 so that one boy received 12 cents less than three times as much as the other. How was the money divided?

Mathematics
2 answers:
JulijaS [17]3 years ago
5 0

Answer:

first one take 1.5$ and the second one take 1.86$

Step-by-step explanation:

stepan [7]3 years ago
5 0

x + y = 3.36 --> the boys are splitting $3.36

x = 3y - .12 --> one boy received $.12 less than 3 times as much as the other

--> substitute the second equation for the x in the first equation

(3y - .12) + y = 3.36 --> combine like terms

4y - .12 = 3.36 --> add .12 to both sides of the equation

4y = 3.48 --> divide both sides by 4

y = .87

the other boy gets $0.87

substitute into x = 3y - 12

x = 3(.87) - .12

x = 2.61 - .12

x = 2.49

the first boy gets $2.49

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Consider the following system of equations:
IrinaK [193]

Answer:

x = 6 ; y = -9

Step-by-step explanation:

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<h3>What are the signs of the sine and of the cosine in each quadrant?</h3>

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Hence, since the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

More can be learned about quadrants at brainly.com/question/28021191

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