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Ivenika [448]
3 years ago
15

The data represents the body mass index? (bmi) values for 20 females. construct a frequency distribution beginning with a lower

class limit of 15.015.0 and use a class width of 6.06.0. does the frequency distribution appear to be roughly a normal? distribution?
Mathematics
1 answer:
Reil [10]3 years ago
5 0
Given the data below <span>representing the body mass index (bmi) values for 20 females.
17.7     33.5     26.9     22.7     22.2     29.9     23.6     18.3     27.7     23.4     19.2     25.9     22.9     37.7     31.6     28.1     44.9     31.6     25.2     23.9

From the data above, we construct a frequency distribution beginning with a lower class limit of 15.0 and use a class width of 6.0 as follows:

Class iinterval: 15.0 - 21.0   21.0 - 27.0   27.0 - 33.0   33.0 - 39.0   39.0 - 45.0
Frequency:              3                  9                  5                   2                  1

From the frequency table, it can be seen that the frequencies started low, increased to a point and then decrease. It can also be seen that the highest frequency of the data is not at the center of the distribution, so the distribution is not symetric.

Therefore, the frequency distribution does not appear to be roughly a normal distribution, because, "although the frequency start low, increase to some maximum, then decrease, the distribution is not symmetric."</span>
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3 years ago
Once there was a fox in a jungle. He was so hungry that he started moving in the forest searching for food. complete the story
kati45 [8]

Answer:

Step-by-step explanation:

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8 0
2 years ago
What are the key aspects of the graph of f(x) = x2 - 62,<br> where b is a real number?
8090 [49]

Answer:

The x intercepts are b , - b

The y-intercept is - b²

The vertex is (0 , - b²)

The axis of symmetry of the function is the y-axis

Step-by-step explanation:

* Lets explain the key aspects of the quadratic function

- There are many key aspects in a quadratic graph such as:

# x-intercepts

# y-intercept

# The vertex

# Axis of symmetry

* Lets solve the problem

∵ f(x) = x² - b² is a quadratic function

∵ The general form of the quadratic function is f(x) = Ax² + B(x) + C

   where A , B , C are constant

∴ A = 1 , B = 0 , C = -b²

- To find the x-intercept put f(x) = 0

∵ f(x) = x² - b²

∴ x² - b² = 0 ⇒ add b² for both sides

∴ x² = b² ⇒ take √ for both sides

∴ x = ± b

∴ The x intercepts are b , - b

- To find the y-intercept put x = 0

∵ f(x) = x² - b²

∴ f(0) = 0 - b²

∴ f(0) = - b²

∴ The y-intercept is - b²

- The vertex of the function is (h , k) where h = -B/2A and k = f(h)

∵ A = 1 and B = 0

∴ h = 0/2(1) = 0

∵ k = f(h)

∴ k = f(0) = 0 - b² = - b²

∴ k = - b²

∴ The vertex is (0 , - b²)

- The axis of symmetry of the quadratic function is a vertical line

  passes through the vertex of it and its equation is x = h

∵ h = 0

∴ The equation of the axis of symmetry is x = 0

∵ The equation of the y-axis is x = 0

∴ The axis of symmetry of the function is the y-axis

7 0
2 years ago
Cada par de puntos determina una recta con la pendiente dada. Halla el valor de la incógnita en cada caso: a. (3,2);(4,x); m=1 b
True [87]

Answer:

a=3,b=0,c=5,d=-4/21

Step-by-step explanation:

The formule we use to get the slope is:

m = \frac{y2-y1}{x2-x1}

a. (3,2);(4,x); m=1

\frac{x-2}{4-3}=1  → x= (1)(4-3)+2 → 3

b. (b,-1);(2,-2); m=-1/2

\frac{-2-(-1)}{2-b}=\frac{-1}{2}  → -1= (\frac{-1}{2})(2-b) →  \frac{-1}{\frac{-1}{2} }-2 → 0

c. (5,d);(9,2); m=-3/4

\frac{2-d}{9-5}=\frac{3}{4}  →  d= (\frac{-3}{4})(9-5)-2 → 5

d. (-1/3,3/4);(h,5/6); m=7/12

\frac{\frac{5}{6}-\frac{3}{4}  }{h-\frac{-1}{3} }=\frac{7}{12}   →  \frac{5}{6}-\frac{3}{4}=  \frac{7}{12} ({h-\frac{-1}{3} })  →  \frac{-4}{21}

We get this equation with the original one:

y=mx+b

There are three  forms of linear equations:

point-slope form y2-y1=m(x2-x1)

standard form Ax + By + C = 0 or Ax + By = C

and slope-intercept form y=mx+b

4 0
3 years ago
You have a list of 1,000 random, normally distributed numbers with a mean of 20 and a standard deviation of 3. Which statement i
Ludmilka [50]
You're going to have to work out the z-scores of both values in each option and see if it makes sense.

n = m + sz

The mean is 20 and the standard deviation is 3.

So let's find try the z-scores of the outer range values and determine their probabilities:

from 14-20:

n = m + sz
20 = 20 + 3z and 14 = 20 + 3z
0 = 3z and -6 = 3z
z = 0 and z = -2

So now using a z-score table, such as the one below, find the probabilities.

z = 0 is easy, it's 0.5
z = -2 is 0.02275

Subtract the smaller from the larger to get the probability of getting in the range:

0.5 - 0.02275 = 0.47725 (so times 1000, you get 477.25, which is not about 340, so this option is wrong)
---
Now trying option 2, from 17-29:

n = m + sz
29 = 20 + 3z and 17 = 20 + 3z
9 = 3z and -3 = 3z
z = 3 and z = -1

0.99865 - 0.158655 = 0.839995 (not 680, so not the answer)
---
Now trying option 3, from 20-23:

n = m + sz
23 = 20 + 3z and 20 = 20 + 3z
3 = 3z and 0 = 3z
z = 1 and z = 0

0.841345 - 0.5 = 0.341345 (close to 340, so is your answer)
8 0
2 years ago
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