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3 years ago

Write the point-slope form of the line that passes through the points (-2, 1) and (0, 1). Identify (x1, y1) as (-2, 1).

1 answer:

kondor19780726 [428]3 years ago

4 0

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -2 &,& 1~) 
% (c,d)
&&(~ 0 &,& 1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-1}{0-(-2)}\implies \cfrac{1-1}{0+2}\implies \cfrac{0}{2}\implies 0
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=0[x-(-2)]\implies y-1=0(x+2)$

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3 years ago

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3 years ago

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3 years ago

Which algebraic expression is a polynomial with a degree of 3?

Irina18 [472]

Option a: $4x^{3} -\frac{2}{x}$

Option b: $2y^{3} +5y^{2} -5y$

Option c: $3y^{3} -\sqrt{4y}$

Explanation:

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Hence, $4x^{3} -\frac{2}{x}$ is a polynomial with a degree of 3.

Hence, Option a is the correct answer.

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From the expression $2y^{3} +5y^{2} -5y$ , the highest degree of the polynomial is 3.

Hence, $2y^{3} +5y^{2} -5y$ is a polynomial with a degree of 3.

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Hence, $3y^{3} -\sqrt{4y}$ is a polynomial with a degree of 3.

Hence, Option c is the correct answer.

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2 years ago

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