The intersection of lines b and c I think
If the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.
Given two vectors be 4i-6j and -i-5j.
We are required to find the angle between vectors 4i-6j and -i-5j.
A vector is basically an equation involving a linear combination of vctors with possibly unkown coefficients. Vector is basically a quantity that has both magnitude and direction but not possition.
Angle is basically measure of inclination of something with the surface.
The angles between two vectors can be find out by the following formula:
cos Θ=[dot product of both the vectors/(product of magnitude of both the vectors)
cos Θ=[4*(-1)+(-6)*(-5)]/
cos Θ=(-4+30)/
cos Θ=26/
cos Θ=26/26.77
cos Θ=0.7070
Θ=(0.707)
Θ=45.008
Approximately 45°.
Hence if the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.
Learn more about vectors at brainly.com/question/25705666
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Answer:
D
Step-by-step explanation:
Answer:
D) log₁₀20x⁵-1 and E) log₁₀(2x⁵)
Step-by-step explanation:
5log₁₀x+log₁₀20-log₁₀10
5log₁₀x+log₁₀20-1
log₁₀x⁵+log₁₀20-1
log₁₀20x⁵-1 (Option D)
5log₁₀x+log₁₀20-log₁₀10
log₁₀20x⁵-log₁₀10
log₁₀(20x⁵/10)
log₁₀(2x⁵) (Option E)
Answer: wow thank you
Step-by-step explanation: