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3 years ago

Write a rule for the linear function in the table.

Mathematics

1 answer:

Firlakuza [10]3 years ago

4 0

I don't know =(
soooorrrryyyyyyyyyyyyyyyyyyyy

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What is the domain of the following function

inysia [295]

Answer:

All real numbers

Step-by-step explanation:

The function shown above is of the second degree. All of the domains of second degree functions represent all real numbers.

8 0

4 years ago

Prove or disprove that (1)/(1-cot x) is the same as (sin x)/(sin x - cos x)

SIZIF [17.4K]

$\dfrac{1}{1-\cot x}=\dfrac{\sin x}{\sin x-\cos x}\\\\L_s=\dfrac{1}{1-\dfrac{\cos x}{\sin x}}=\dfrac{1}{\dfrac{\sin x}{\sin x}-\dfrac{\cos x}{\sin x}}=\dfrac{1}{\dfrac{\sin x-\cos x}{\sin x}}=\dfrac{\sin x}{\sin x-\cos x}=R_s$

$\text{Used:}\\\\\cot x=\dfrac{\cos x}{\sin x}$

7 0

3 years ago

Write a quadratic function f whose zeros are 6 ad 5

dolphi86 [110]

46!! Stay safe! That’s the answe

3 0

3 years ago

What’s the lowest term of 3/4-2/6=

lana66690 [7]

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5 0

3 years ago

Musah stands at the centre of a rectangular field. He first takes 50 steps north, then 25 steps west and finally 50 steps on a b

Natalija [7]

Answer:

Musah's final point from the centre = 60.355 steps

Step-by-step explanation:

From the given information:

Musah stands at the centre of a rectangular field. He first takes 50 steps north, then 25 steps west and finally 50 steps on a bearing of 315°

The sketch for this information can be seen in the attached file below.

How far west is Musah's final point from the centre?

In order to determine how far west is Musah's,

Let d be the distance of how far;

Then d = QR + RS cos θ

In the North West direction,

cos θ = cos 45°

d = 25 + 50( cos 45°)

d = 25 + 50( $\dfrac{1}{\sqrt{2}}$ )

d = 25 + 50( 0.7071)

d =25 + 35.355

d = 60.355 steps

Musah's final point from the centre = 60.355 steps

5 0

4 years ago