Three coins are placed in a bag. Each coin is labeled "1", "2", or "3". A coin is drawn from the bag, recorded, and then placed
back in the bag. Estimate the probability that the coin labeled "1" will be drawn next. 3 3 2 2 1 1 3 3 2 2
1 answer:
Answer:
1/3 or 33.33%
Step-by-step explanation:
Each draw is an independent event, and it doesn't happen what happened before, since the coin is placed back in the bag, recreating the same scenario.
There are 3 coins in the bag... so drawing out the coin labeled '1' is one possibility out of three possible outcomes.
1/3 or 33.33%
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Answer:
x = 13°
Step-by-step explanation:
m<EGF + m< FGH = m<EGH
or, 3x+6+5x-7 = 103°
or, 8x-1 = 103°
or, 8x = 103°+1°
or, x = 104°/8
or, x = 13°
Now,
m<EGF = 3x+6
= 3×13+6
= 39+6
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Step-by-step explanation:
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