All categories

3 years ago

Choose the student who wrote the correct inequality.

Mathematics

2 answers:

svp [43]3 years ago

7 0

Answer:

Tori

Step-by-step explanation:

if youre making over 90 percent of your free throws, then any number (P) greater than 90 is the answer

Jlenok [28]3 years ago

7 0

<h2>Answer:</h2><h2>Toris work;Greater than 90.</h2><h2>Because 90% has to be greater and not less.</h2><h2>~Empress Arianna Mcdonald. </h2>

You might be interested in

a recipe for cooking turkey says to allow 15 minute cooking for each pound of turkey and to add 5 minutes additional cooking tim

marysya [2.9K]

The doctor had the opinion about the boy that it world

hare been better is he had velict

4 0

3 years ago

Construct an explicit rule in function notation for the arithmetic sequence represented in the table. Then determine the value o

strojnjashka [21]

Answer:

After 11 weeks, Darnell′s savings account will have a total of $8,360.

Step-by-step explanation:

The data provided is as follows:

n: 1 2 3 4

f (n): 260 360 460 560

Consider the data for f (n).

The series f (n) follows an arithmetic sequence with a common difference of 100 and first term as 260.

The nth term of an arithmetic sequence is:

$a_{n}=\frac{n}{2}[2a+(n-1)d]$

Compute the value of f (11) as follows:

$f(11)=\frac{11}{2}[(2\times260)+(11-1)\times 100]$

$=5.5\times[520+1000]\\\\=5.5\times 1520\\\\=8360$

Thus, after 11 weeks, Darnell′s savings account will have a total of $8,360.

5 0

3 years ago

30 POINTS HELPPPPPP

riadik2000 [5.3K]

Answer:

$20.40

Step-by-step explanation:

4 0

3 years ago

A dime is what fraction of a dollar?

iren [92.7K]

Answer:

1/10

Step-by-step explanation:

3 0

3 years ago

If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term.

Simora [160]

Consecutive terms in an arithmetic sequence differ by a constant $d$ . So

$5k-1=2k+d$
$6k+2=5k-1+d$
$\implies\begin{cases}3k-d=1\\k-d=-3\end{cases}\implies k=2,d=5$

Denote the $n$ -th term in the sequence by $a_n$ . Now that $a_1=2$ , we have

$a_n=a_{n-1}+5=a_{n-2}+2\cdot5=\cdots=a_1+(n-1)\cdot5$

which means

$a_8=2+(8-1)\cdot5=37$

4 0

3 years ago