What is a demand schedule?

The perimeter of a square is 100 feet and area is 625 square feet . what is the length of each side

Veronika [31]

25 feet each. All you have to do is divide the perimeter by how many sides.

6 0

4 years ago

Read 2 more answers

Write the first three terms in the binomial expansion, expressing the result in simplifies form.

Pani-rosa [81]

You need to foil it out. That's how you get the answer.

(x+4)^20
=
(x+4) x (x+4)^19
=
(x+4)^2 x (x+4)^18
etc.

8 0

3 years ago

Dorothy is using fabric to cover a photo album the width of the fabric is 5/8 of a yard the area of the fabric is 5/16 square ya

saul85 [17]

For this case we assume that the photo album is rectangular in shape and therefore the fabric too. By definition, the area of a rectangle is given by:

$A = a * b$

Where:

a: It is the length of the rectangle

b: It is the width of the rectangle

According to the problem data we have to:

$b =\frac {5}{8} \yard\\A = \frac {5} {16} \ yards ^ 2$

Substituting:

$\frac {5} {16} = a * \frac {5} {8}$

We clear "a":

$a = \frac {\frac {5} {16}} {\frac {5} {8}}\\a = \frac {5 * 8} {16 * 5}\\a = \frac {8} {16}\\a = \frac {1} {2}$

Thus, the length of the fabric is $\frac {1} {2} yards.$

ANswer:

The length of the fabric is $\frac {1} {2} yards.$

5 0

4 years ago

If Charles lost 20 pounds, he would weigh seven times as much as his dog. Together they weigh 200 pounds. How much does each wei

barxatty [35]

Answer: Weight of Charles = 177.5 pounds

Weight of dos = 22.5 pounds.

Step-by-step explanation:

Let x = Weight of Charles

y = Weight of dog.

As per given , we have the following system of linear equation :

$x+y=200--------(i)\\\\x-20=7y-----------(ii)$

We can write (ii) as :

$x-7y=20---(iii)$

Subtract equation (iii) from (i) , we get

$8y=180\\\\ y=\dfrac{180}{8}=22.5$

Put this value in (1) , we get

$x+22.5=200\Rightarrow\ x=200-22.5=177.5$

Hence , Weight of Charles = 177.5 pounds

Weight of dos = 22.5 pounds.

6 0

3 years ago

Find the equation of the line of the circle passing through the points (1,2) (3,-4) (5,-6)

Cerrena [4.2K]

Answer:

(x-11)² + (y-2)² = 10²

Step-by-step explanation:

Given circle passes through

P(1,2), Q(3,-4), R(5,-6)

Assume following circle with centre O(a,b) and radius r contains P,Q,R.

(x-a)²+(y-b)² = r^2 ...........(1)

Substitute P in (1) and expand, simplify

(1-a)²+(2-b)²=r²

a²+b² -2a-4b+5-r²=0 .......(2)

Similarly, substitute Q in (1) and expand, simplify

(3-a)²+(-4-b)² = r²

a²+b²-6a+8b+25-r²=0 ...........(3)

Similarly, substitute R in (1) and expand, simplify

(5-a)²+(-6-b)² = r²

a²+b²-10a+12b+61-r²=0 ...........(4)

We can now eliminate a^2 and b^2 by simple subtractions

(2) - (3)

4a-12b-20 = 0 ..........(5)

(3) - (4)

4a-4b-36 = 0 .............(6)

Finally, (6) - (5) and solve for b

8b - 16 = 0

b=2 ..............................(7)

substitute b in (5) and solve for a

4a-12(2) -20 =0

4a=44

a=11 ................................(8)

Finally, substitute a & b in (2) to solve for r

r^2 = 11²+2²-2*11-4*2+5 = 121+4-22-8+5 = 100

r=sqrt(100) = 10 (positive value only)

therefore the equation of the circle is

(x-11)² + (y-2)² = 10²

6 0

3 years ago