I think so but I'm not sure
Step-by-step explanation:
<u>Permutations</u>:
n<em>P</em><em> </em>r = n!/(n + r)!
<u>Combinations</u>:
<em>nCr</em> = n!/(n - r)!r!
c - combination
p - permutations
Since in both the problems they are looking for different groups, it is a combination problem. the order in which the people were selected in each group is not important, what is required are different groups.
<u>A.</u>
n = 51
r = 3
51<em>C</em><em> </em>3 = 51! / ((51 - 3) ×3!)
<em>51C</em><em>3</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>8</em><em>2</em><em>5</em><em> </em>groups
<u>OR:</u>


<em><u>B</u></em><em><u>.</u></em>


It will be 20 because if the number next to it is 5 and above you will raise it to 21, but if the number is 4 or less, you don’t do anything. So therefore, the answer will be 20.
Answer:B AB ≅ DE
Step-by-step explanation:
Since the triangles are congruent and AB and DE are the same line on both triangles they’re the same.
Roy is correct. When you multiply fractions, you multiply the numerator of one fraction and the other numerator of the other fraction, and vice versa for denominator.
7 x 3 = 21 (Numerators)
——- —-
3 x 8 = 32 (Denominators)
I hope this helped!