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Zepler [3.9K]
3 years ago
13

Andrea rents a bike for a day. The rental charges can be determined by

Mathematics
2 answers:
Greeley [361]3 years ago
4 0
Https://www.cymath.com/answer?q=%205%2B4i%2F6%2B8i
kolezko [41]3 years ago
4 0

Answer: Hence, the unit rate would be $0.5.

Step-by-step explanation:

Since we have given that

R=\$0.5d

Here, R is the rental charges.

d is the number of days she rents the bike.

We need to find the unit rate.

So, unit rate would be

\dfrac{R}{d}=\$0.5

Hence, the unit rate would be $0.5.

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a toy manufacturer has designed a new piece for use in building models. It is a cube with side lengths 7 mm and has a 3 mm in di
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Given that the cubical piece has side (s) 7 mm, and a cylindrical hole of diameter (d) as 3 mm.

The volume of the piece can be calculated as,

\begin{gathered} \text{Volume of piece}=\text{ Volume of cube}-\text{ Volume of cylinder} \\ V=s^3-\frac{\pi}{4}d^2s \\ V=7^3-\frac{\pi}{4}(3)^2(7) \\ V=343-\frac{63\pi}{4} \\ V\approx293.52mm^3 \\ V\approx293.52\times10^{-9}\text{ }m^3 \end{gathered}

It is mentioned that the material costs $207 per cubic meter, so the cost (c) of 1 piece is calculated as,

\begin{gathered} \text{Cost of 1 piece}=\text{ Cost per unit volume}\times\text{ Volume of 1 piece} \\ c=207\times293.52\times10^{-9} \\ c\approx60758.64\times10^{-9} \end{gathered}

This is the cost (in dollars) for 1 piece.

Given that the manufacturer wants to produce 1,000,000 such pieces, so the total cost (TC) is calculated as,

\begin{gathered} \text{Total Cost}=\text{ Cost per piece}\times\text{ No. of pieces} \\ TC=60758.64\times10^{-9}\times1,000,000 \\ TC=60758.64\times10^{-9}\times10^6 \\ TC=60758.64\times10^{-3} \\ TC=60.75864 \\ TC\approx60.75 \end{gathered}

Thus, the total prototypes will cost around $60.75

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1 year ago
Matthew goes hiking every 12 days and swimming every 6 days. He did both
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a car traveled 36 miles in 45 minutes. the car traveled at a constant speed. it the car continues to travel at this rate which e
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The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the func
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Answer:

<em>A) (-5,7)</em>

Step-by-step explanation:

<u>Functions and Relations</u>

A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

\boxed{A)\ (-5,7)}

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