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Aleks04 [339]
2 years ago
10

Problem Page Last year, Donna had $30,000 to invest. She invested some of it in an account that paid 9% simple interest per year

, and she invested the rest in an account that paid 6% simple interest per year. After one year, she received a total of $1950 in interest. How much did she invest in each account?
Mathematics
1 answer:
Nesterboy [21]2 years ago
7 0

Answer:

The money invested in the account 1 was $25,000 and in the account 2 was 5,000.

Step-by-step explanation:

In this case we can formulate a system of equations that could find the amount invested in each account, this is:

Money invested in the account 1 is A

Money invested in the account 2 is B

Eq. 1: A+B=30,000

Eq. 2: \frac{9}{100} *A+\frac{6}{100} *B=1,950

Replacing the equation 1 in 2, this is:

\frac{9}{100} *(30,000-B)+\frac{6}{100} *B=1,950Clearing the value of B:[tex]2,700-0.09B+0.06B=1,950

2,700-1,950=0.09B-0.06B

750=0.03B

B=\frac{750}{0.03}

B=25,000

Now, we can find A:

A=30,000-B\\A=30,000-25,000\\A=5,000

The money invested in the account 1 was $5,000 and in the account 2 was 25,000.

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