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Dima020 [189]
3 years ago
9

What is 555.55 rounded to the nearest tenth?

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0
5 always rounds up so the answer is 555.6
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At your school, the building is 20 feet tall, a tree's height is 252 inches, and the flagpole is 6 yards high. Which of the thre
timurjin [86]
First, all the heights have to be converted to similar units, say feet.

Therefore,
Building= 20 feet
Tree = 252*0.083333 = 21 feet
Flagpole = 6*3 = 18 feet

The tallest of the three is the tree and thus should cast the longest shadow. However, it should be noted that at exactly noon when the sun is overhead, all the three will have equal length of shadow (that is, 0 feet long).
3 0
3 years ago
If the door to the library is at (2, 4), the door to the mall is at (8, 2), and one
guapka [62]

Answer:

6 miles

Step-by-step explanation:

The distance formula is expressed as;

D = √(x2-x1)²+(y2-y1)²

D = √(2-4)²+(8-2)²

D = √(-2)²+(6)²

D = √4 + 36

AD = √40

AD = 6.32

Hence the approximate distance between the library  and the mall is 6 miles

5 0
3 years ago
Does the equation below define a liner function​
Komok [63]
<h3>Answer: No, this function is not linear</h3>

This function is a hyperbola. It graphs out two disjoint curves. A linear function produces a single straight line graph. All linear functions can be written in the form y = mx+b. The x being in the denominator is one indicator we cannot write the original equation in the form y = mx+b.

y = 3/x is the same as xy = 3; this tells us every point on y = 3/x has its (x,y) coordinate pair multiply to 3.

8 0
3 years ago
A car is traveling at a steady speed. It travels 1 3/4 miles in 2 1/3 minutes. how far will it travel in 21 minutes? in 1 hour?
GaryK [48]

Answer:

Step-by-step explanation:

1¾ miles/(2⅓ minutes) = (7/4 miles)/(7/3 minutes) = ¾ mile/minute

21 minutes × ¾ mile/minute = 15.75 miles

60 minutes × ¾ mile/minute = 45 miles

8 0
3 years ago
What is the solution to the equation? Please explain!
Alexus [3.1K]
J: there is no solution
4 0
2 years ago
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