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Sedaia [141]
3 years ago
14

Compare and contrast a linked list and an array.

Computers and Technology
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

Differences between arrays and linked list are as following:-

  1. Arrays store elements in contiguous memory location while the linked list does not store elements at contiguous memory location it connects nodes at different memory location.
  2. Array has index to directly access the elements there are no indexes in linked list to directly access the elements.
  3. Linked list contains Nodes which contains the data and the address of the next Node while the array contains only the data in the block.
  4. Traversal over the arrays is easy while the traversal over the linked list is difficult as compared to arrays.
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Jack, a skillful hacker targeted a major banking services firm located in Japan, using the LOIC (Low Orbit Ion Cannon) tool, Jac
Elenna [48]

Answer:

denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack)

Explanation:

Denial-of-service attack -

It is a type of cyber attack , where the hacker can create a machine or any network resource , which is capable to disrupt the server of the host , with the help of the internet , is referred to as the denial of service attack .

The task is accomplished with by flooding the host with many superfluous requests , which can overload the system .

In case of the distributed denial-of-service attack , the flooding is done by many different sources .

Hence , from the given scenario of the question ,

The correct answer is  denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack) .

4 0
3 years ago
In matlab how would this specific code be written and how could I ask the user to enter a vector of coefficients for the polynom
solniwko [45]

Answer:

Explanation:

that is correct 1234

7 0
3 years ago
Write the half function. A function call and the functionprototype
EastWind [94]

Answer:

C code for half()

#include<stdio.h>

void half(float *pv);

int main()

{

float value=5.0;  //value is initialized  

printf ("Value before half: %4.1f\n", value); // Prints 5.0

half(&value);  // the function call takes the address of the variable.

printf("Value after half: %4.1f\n", value); // Prints 2.5

}

void half(float *pv) //In function definition pointer pv will hold the address of variable passed.

{

*pv=*pv/2;  //pointer value is accessed through * operator.

}

  • This method is called call-by-reference method.
  • Here when we call a function, we pass the address of the variable instead of passing the value of the variable.
  • The address of “value” is passed from the “half” function within main(), then in called “half” function we store the address in float pointer ‘pv.’ Now inside the half(),  we can manipulate the value pointed by pointer ‘pv’. That will reflect in the main().
  • Inside half() we write *pv=*pv/2, which means the value of variable pointed by ‘pv’ will be the half of its value, so after returning from half function value of variable “value” inside main will be 2.5.

Output:

Output is given as image.

3 0
3 years ago
Your boss is trying to modify a PDF file that he made a year ago. He asks you what he can use to do this. Which of the selection
Masteriza [31]
The answer is b. Office 2013
3 0
3 years ago
Read 2 more answers
Which transfer of learning occurs when the performance of a maneuver interferes with the learning of another maneuver?
Nutka1998 [239]

Answer:

Negative transfer of learning

Explanation:

Negative transfer of learning occur when the knowledge you've acquired in the past is/are interfering with the one(s) you are currently acquiring.

Example: learning a new language that have some differences in pronunciation from the previous one, changing from a right-sided vehicles to a left-sided vehicles etc.

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