Answer: the picture is the answer
Explanation:
Please use Gauss’s law to find the electric field strength E at a distance r from the center of a sphereof radius R with volume
charge density ???? = cr 3 and total charge ????. Your answer should NOT contain c. Be sure to consider regions inside and outside the sphere.
1 answer:
Answer:
See the explaination for the details.
Explanation:
Gauss Law states that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the field.
According to the Gauss law, the total flux linked with a closed surface is 1/ε0 times the charge enclosed by the closed surface.
Please kindly check attachment for the step by step explaination of the answer.
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The spring constant is 66.7 N/m
Explanation:
First of all, we have to find the magnitude of the force acting on the spring. This is equal to the weight of the mass hanging on the spring, which is:
where:
m = 0.50 kg is the mass of the object
is the acceleration of gravity
Substituting,
Now we can use Hookes' law to find the constant of the spring:
where
F is the force applied
k is the spring constant
x is the stretching of the spring
Here we have:
F = 5 N
While the stretching is
x = 0.075 m
Therefore, ignoring the negative sign in the formula (which only tells us the direction), we find the spring constant:
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