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USPshnik [31]
2 years ago
15

If the partial pressure of nitrogen in the human body is approximately 593 mm hg at sea level, the partial pressure of nitrogen

cannot be ______________ in a scuba diver that is at a depth of 30 feet.
Physics
1 answer:
joja [24]2 years ago
8 0

If the partial pressure of nitrogen in the human body is approximately 593 mm hg at sea level, the partial pressure of nitrogen cannot be 760mm Hg in a scuba diver that is at a depth of 30 feet.

Nitrogen narcosis :

The partial pressure of nitrogen increases with pressure, which produces a narcotic effect. Nitrogen narcosis affects both scuba divers and free divers. It causes depression of the central nervous system, which leads to feelings of euphoria, disorientation and irrational behavior. Divers need to consider absorption rates of different gases in order to avoid conditions such as nitrogen narcosis, and decompression sickness.

What is the partial pressure of the nitrogen?

Therefore, at sea level, where atmospheric pressure is known to be 760 mm Hg, the partial pressures of the various gases can be estimated to have partial pressures of approximately 593 mm Hg for nitrogen, 160 mm Hg for oxygen, and 7.6 mm Hg for argon.

Learn more about nitrogen partial pressure :

brainly.com/question/15268421

#SPJ4

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Science help please!
OLga [1]

Answer:

104 N

Explanation:

m = 1300 kg

a = 0.08m/s^2

F = 1300*0.08

F = 104 N

Newtons is the unit of force.

3 0
3 years ago
A 0.12 kg bird is flying at a constant speed of 7.8 m/s. what is the birds conetic energy?
lana [24]
KE=1/2mv^2 - equation for kinetic energy
KE=(1/2)(0.12 kg)((7.8 m/s)^2 - plug it into the formula
KE=(0.06 kg)(60.84 m/s) - multiply 1/2 to the mass and square the speed
KE= 3.7 J - answer
Hope this helps
7 0
4 years ago
Read 2 more answers
A wave has a frequency of 35 Hz and a wavelength of 15 meters,<br> what is the speed of the wave?
Mila [183]

Answer:

f lamda = c

Explanation:

525 m/s is the speed

5 0
3 years ago
Learning Goal: To understand the behavior ofthe electric field at the surface of a conductor, and itsrelationship to surface cha
Ivan

Complete Question

The complete question is shown on the first uploaded image  

Answer:

a   it is always zero

b  0

c  \eta  =  -\epsilon _o E

Explanation:ss

Here the  net charge is  on the outer surface of the conductor thus this means that the net charge inside the conductor is zero

Generally the charge density of a conductor is dependent on the charge per unit area  which implies that the charge density is dependent on the net charge  so this  means that the charge density inside the conductor is zero

 

Generally the direction of electric field this from the  positive charge to the negative charge  so from the question we can deduce  that the negative charge is located on the surface of the conductor

    So We can mathematically define the charge density on the surface of the electric field as

             ∮E \cdot dA =  \frac{-Q}{\epsilon _o}

Where E is the electric field

          dA change in unit area

           -Q is the negative charge

          \epsilon _o  is the permittivity of free space

So

          EA  =  \frac{-Q}{\epsilon _o }

           \frac{Q}{A}  =  -\epsilon _o E

          \eta  =  -\epsilon _o E

Where \eta is the charge density

   

8 0
4 years ago
The current through a 10 ohm resistor connected to a 120 volt power supply is
Leno4ka [110]

Answer:I=12 A

Explanation:

Given

Resistance R=10 \Omega

Voltage V=120 V

According to ohm's law current through a conductor is directly proportional to the voltage applied.

V\propto I

V=IR

where V=Voltage

I=Current

R=resistance

I=\frac{V}{R}

I=\frac{120}{10}

I=12 A

4 0
3 years ago
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