A cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 9 inches. The height of the cone is 18 inc

hes.
Use π = 3.14.

What is the relationship between the volume of this cylinder and this cone? Explain your answer by determining the volume of each and comparing them. Show all your work.

Mathematics

1 answer:

Elan Coil [88]3 years ago

4 0

$\sf Cylinder ~volume = \pi r^2 h \\ \\ v = \pi (4)^2(9) \\ \\ v=\pi (16)(9) \\ \\ v=144 \pi \\ v=452.16\\ \\ \\ Cone~volume = \frac{1}{3} \pi r^2 h \\ \\ v = \frac{1}{3} \pi (4)^2 (18) \\ \\ v=96 \pi \\ v=301.44 \\ \\ \\ The~ volume ~of ~a ~cylinder ~is~ 1.5~ times~ more ~than ~the ~volume ~of~a~cone.$

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Use the diagram to answer the question

koban [17]

Answer:

$m\angle EFG=52^{o}$

Step-by-step explanation:

We have been given that line m is parallel to line p, $m\angle HEF=39^{o}$ and $m\angle IGF=13^{o}$ .

Since line m is parallel to line p and EJ is a transversal, so measure of angle EJG will be 39 degrees as angle EJG is alternate interior angle of angle HEF. Both angles are inside parallel lines m and p and on opposite side of transversal EJ.

We can see that angle EFG is exterior angle of triangle GFJ. Since the measure of an exterior angle of a triangle equals to the sum of the opposite interior angles.

We can see that angle IGF and angle EJG are opposite interior angles of angle EFG.

$m\angle EFG=m\angle IGF+m\angle EJG$