Distribute ^3 to both 6 and k^3
6^3 = 6 x 6 x 6 = 216
(k^3)^3 = k^9 (because you are multiplying k^3 x k^3 x k^3)
216k^9, or C) is your answer
hope this helps
Answer:f(3)=26,f(6)=215
Step-by-step explanation:
f(x)=3^x-1
f(3)=3^3-1
f(3)=3x3x3-1
f(3)=27-1
f(3)=26
f(6)=6^3-1
f(6)=6x6x6-1
f(6)=216-1
f(6)=215
Triangle ABC has angles 130, 15 and 35
Triangle DEF has angles 35, 15, and 130
4) The triangles have 3 pairs of congruent angles.