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3 years ago

Find the volume of the box with the edges x+2 2x+1 3x-1

2 answers:

ioda3 years ago

6 0

V=edge*edge*edge
V=(x+2)+(2x+1)(3x-1)
V=(x*2x+x*1+2*2x+2*1)(3x-1)
V=(2x²+x+4x+2)(3x-1)
V=(2x²+5x+2)(3x-1)
V=2x²*3x-2x²*1+5x*3x-5x*1+2*3x-2*1
V=6x³-2x²+15x²-5x+6x-2
V=6x³+13x²+x-2. Hope it help!

Margaret [11]3 years ago

3 0

(x+2)(2x+1)(3x-1)
(2x^2+4x+x+2) (3x-1)
(2x^2+5x+2)(3x-1)
6x^3+15x^2+6x-2x^2-5x-2
6x^3+13x^2+x-2

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lidiya [134]

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3 years ago

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SSSSS [86.1K]

PEMDAS states that the value in the parenthesis should be evaluated first:
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3 years ago

Read 2 more answers

Find the sum. 7/30 + 9/20 PLS

e-lub [12.9K]

Answer:

41/60

Step-by-step explanation:

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