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castortr0y [4]
3 years ago
5

A speed walker covered 4 1/2 mi in 3/4 hour. How far will he walk in 3/4 hour if he walks

Mathematics
1 answer:
Pavel [41]3 years ago
4 0

Answer:

A=27/4       B=2.25

Step-by-step explanation:

4 and 1/2 also equals 18/4.

18/4+1/2(18/4)=18/4+9/4

18+9=27

Answer is 27/4

B)=4.5/2=2.25

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A partial variation has an equation of the form y=mx+b, where m represents the
Nastasia [14]

Answer:

false

Step-by-step explanation:

b represents y value

6 0
3 years ago
Please help me with this question
likoan [24]

Answer:

  P = (2, 3)

Step-by-step explanation:

P is a local minimum, so can be found from the upper zero of the derivative.

  y' = 0 = 3x^2 -8x +4

  0 = (3x -2)(x -2)

  x = 2/3, x = 2

So, the x-coordinate of P is 2. The y-coordinate is found by evaluating the function:

  y = ((x -4)x +4)x +3 = ((2 -4)2 +4)2 +3 = 3

The coordinates of P are (2, 3).

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A graphing calculator confirms this result.

6 0
3 years ago
Can anyone help me with this please. <br><br><br> x^2– 5x – 24 = 0
antiseptic1488 [7]
X = -3, 8
hope this helps
8 0
3 years ago
Tammy bought a nightstand that was marked down 60% from an original price of $50. If she paid 10% sales tax, what was the total
AURORKA [14]

Answer: the total cost of the nightstand is $22

Step-by-step explanation:

The original price of the night stand is $50. If the original price of the night stand was marked down by 60%, it means that the amount of money by which it was reduced would be

60/100 × 50 = 0.6 × 50 = 30

The new selling price would be

50 - 30 = $20

If she paid 10% sales tax,the amount of tax paid would be

10/100 × 20 = 0.1 × 20 = 2

Therefore, the total cost of the nightstand would be

20 + 2 = $22

7 0
3 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
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